Quadrilaterals | FIO

Question 11

Find the remaining angles in the following trapeziums—

Question diagram 1
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Solution

We will use the properties of parallel lines and trapeziums to find the unknown angles.

Step 1 — Finding angles in the first trapezium

Let us look at the first trapezium. The arrows on the top and bottom sides tell us these sides are parallel. When two parallel lines are cut by another line (called a transversal), the angles between the parallel lines on the same side of the transversal are called consecutive interior angles. These angles always add up to 180\mathbf{180^\circ}.

Let the bottom-left angle be DD and the bottom-right angle be CC. Let the top-left angle be AA and the top-right angle be BB. From the diagram, we are given: Angle D=135D = 135^\circ Angle C=105C = 105^\circ

Since the top and bottom sides are parallel, angle AA and angle DD are consecutive interior angles. So, their sum is 180180^\circ.

A+D=180A + D = 180^\circ

A+135=180A + 135^\circ = 180^\circ

A=180135A = 180^\circ - 135^\circ

A=45\boxed{A = 45^\circ}

Similarly, angle BB and angle CC are consecutive interior angles. So, their sum is 180180^\circ.

B+C=180B + C = 180^\circ

B+105=180B + 105^\circ = 180^\circ

B=180105B = 180^\circ - 105^\circ

B=75\boxed{B = 75^\circ}

Diagram 1

Step 2 — Finding angles in the second trapezium

Let us look at the second trapezium. The arrows on the top and bottom sides tell us these sides are parallel. The tick marks on the left and right sides mean these two non-parallel sides are equal in length. This type of trapezium is called an isosceles trapezium. In an isosceles trapezium, the base angles (angles on the same parallel side) are equal.

Let the bottom-left angle be DD and the bottom-right angle be CC. Let the top-left angle be AA and the top-right angle be BB. The diagram shows one of the bottom angles is 100\mathbf{100^\circ}. Let us assume this is angle DD.

Since it is an isosceles trapezium, the base angles CC and DD are equal.

C=DC = D

C=100C = 100^\circ

C=100\boxed{C = 100^\circ}

Now, we use the property of consecutive interior angles, just like in Step 1. Angle AA and angle DD are consecutive interior angles, so their sum is 180180^\circ.

A+D=180A + D = 180^\circ

A+100=180A + 100^\circ = 180^\circ

A=180100A = 180^\circ - 100^\circ

A=80\boxed{A = 80^\circ}

Similarly, angle BB and angle CC are consecutive interior angles, so their sum is 180180^\circ.

B+C=180B + C = 180^\circ

B+100=180B + 100^\circ = 180^\circ

B=180100B = 180^\circ - 100^\circ

B=80\boxed{B = 80^\circ}

Diagram 2

Answer

(i) The remaining angles are 45\mathbf{45^\circ} and 75\mathbf{75^\circ}. (ii) The remaining angles are 80\mathbf{80^\circ}, 80\mathbf{80^\circ}, and 100\mathbf{100^\circ}.

More questions in FIO

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Q2

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(i) 30° (ii) 40° (iii) 90° (iv) 140°

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Q4

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Q5

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Q6

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Q7

Using the diagonal properties, construct a parallelogram whose diagonals are of lengths 7 cm and 5 cm, and intersect at an angle of 140°.

Q8

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Q9

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Q10

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Q11

Find the remaining angles in the following trapeziums—

Q12

Draw a Venn diagram showing the set of parallelograms, kites, rhombuses, rectangles, and squares. Then, answer the following questions—

(i) What is the quadrilateral that is both a kite and a parallelogram? (ii) Can there be a quadrilateral that is both a kite and a rectangle? (iii) Is every kite a rhombus? If not, what is the correct relationship between these two types of quadrilaterals?

Q13

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Q14

Construct a square with diagonal 6 cm without using a protractor.

Q15

CASE is a square. The points U, V, W and X are the midpoints of the sides of the square. What type of quadrilateral is UVWX? Find this by using geometric reasoning, as well as by construction and measurement. Find other ways of constructing a square within a square such that the vertices of the inner square lie on the sides of the outer square, as shown in Figure (b).

Q16

If a quadrilateral has four equal sides and one angle of 90°, will it be a square? Find the answer using geometric reasoning as well as by construction and measurement.

Q17

What type of a quadrilateral is one in which the opposite sides are equal? Justify your answer.

Hint: Draw a diagonal and check for congruent triangles.

Q18

Will the sum of the angles in a quadrilateral such as the following one also be 360°? Find the answer using geometric reasoning as well as by constructing this figure and measuring.

Q19

State whether the following statements are true or false. Justify your answers.

(i) A quadrilateral whose diagonals are equal and bisect each other must be a square.

(ii) A quadrilateral having three right angles must be a rectangle.

(iii) A quadrilateral whose diagonals bisect each other must be a parallelogram.

(iv) A quadrilateral whose diagonals are perpendicular to each other must be a rhombus.

(v) A quadrilateral in which the opposite angles are equal must be a parallelogram.

(vi) A quadrilateral in which all the angles are equal is a rectangle.

(vii) Isosceles trapeziums are parallelograms.

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