Constructions and Tilings

When constructing the perpendicular bisector, is it necessary to have the same radius for the arcs above and below XY? Explore this through construction, and then justify your answer.

[Hint 1: Any point that is of the same distance from X and Y lies on the perpendicular bisector.

Hint 2: We can draw the whole line if any two of its points are known.]

Is it necessary to construct the pairs of arcs above and below XY? Instead, can we construct both the pairs of arcs on the same side of XY? Explore this through construction, and then justify your answer.

While constructing one pair of intersecting arcs, is it necessary that we use the same radii for both of them ? Explore this through construction, and then justify your answer.

Recreate this design using only a ruler and compass —

Justify why AB in Fig. 6.4 is the perpendicular bisector.

Can you think of different methods to construct a 90° angle at a given point on a line using a rope?

Construct at least 4 different angles. Draw their bisectors.

Construct the 8-petalled figure shown in Fig. 6.5.

In Step 2 of angle bisection, if arcs of equal radius are drawn on the other side, as shown in the figure, will the line OC still be an angle bisector? Explore this through construction, and then justify your answer.

What are the other angles that can be constructed using angle bisection? Can you construct 65.5° angle?

Come up with a method to construct the angle bisector using a rope.

Construct the following figure.

How do we construct the petals so that they are of the maximum possible size within a given square?

Construct at least 4 different angles in different orientations without taking any measurement. Make a copy of all these angles.

Construct the Fig. 6.6.

Construct 4 pairs of parallel lines in different orientations.

Construct the following figure.

Use support lines in Fig. 6.11 to construct a pointed arch. Make different arches, by changing the radius of the arcs.

Make your own arch designs.

Construct the following figures:

Optical Illusion: Do you notice anything interesting about the following figure? How does this happen? Recreate this in your notebook.

Construct this figure.

[Hint: Find the angles in this figure.]

Draw a line $l$ and mark a point P anywhere outside the line. Construct a perpendicular to the given line $l$ through P.

[Hint: Find a line segment on $l$ whose perpendicular bisector passes through P.]

How can the tangram pieces be rearranged to form each of the following figures?

Are the following tilings possible?

How do we find such A and B?

From X and Y, draw arcs above and below XY, with the same radii. The two points at which the arcs meet, above and below XY, give us A and B, respectively.

Use this to construct an eye.

In Fig. 6.1, join A and B with a line. Where does AB intersect XY, and what is the angle formed between them?

Will the line joining the two points at which the arcs meet, above and below XY, always be the perpendicular bisector of XY, i.e., when XY is of any length, and the arcs are drawn using a radius of any length?

Which two triangles should be congruent for AB to be the perpendicular bisector of XY (that is, O is the midpoint of XY and AB is perpendicular to XY)?

How do we get these different shapes? Try!

Will C and D lie on the perpendicular bisector AB?

Justify the following statement using the facts that we have established.

Any point that has the same distance from X and Y lies on the perpendicular bisector of XY.

Given a line segment XY, how do we draw its perpendicular bisector using only an unmarked ruler and a compass?

Can we extend the method of constructing the perpendicular bisector to construct a 90° angle at any point on a line? Draw a line and mark a point O on it. Construct a 90° angle at point O.

Find a segment of this line for which O is the midpoint.

How do we construct this figure?

What is the angle between two adjacent lines?

How do we construct a 45° angle using only a ruler and a compass?

Construct the following figure.

Draw an angle. Create a copy of this angle using only a ruler and compass.

How do we implement this idea using a ruler and a compass?

How did they make these arches?

Construct this arch shape on a piece of paper.

Let us think about the support lines this figure will need.

For symmetry, we should have $AB = CD$, and $\angle BAD = \angle CDA$. How would you construct these support lines?

Use these support lines to construct an arch. If required, adjust the radii of the arcs to make the arch look more aesthetically pleasing.

How do we construct this shape?

What supporting lines will you use to draw this arch?

Remember 'Wavy Wave' from the Grade 6 Textbook?

The supporting lines are just two line segments of equal length.

If their midpoints are marked, will you be able to construct a pointed arch?

How do we construct a regular pentagon (5-sided figure) and a regular hexagon (6-sided figure)? To begin with, try to construct a pentagon and hexagon with equal sidelengths.

Can we break a regular hexagon into smaller pieces that can be constructed?

Can six congruent equilateral triangles be placed together as in Fig. 6.12? If yes, will it result in a regular hexagon?

Consider this figure. Will the 70° angle fit into the gap? What is the gap angle $\angle AOI$?

We have, $40^\circ + 60^\circ + 50^\circ + 30^\circ + 40^\circ + 90^\circ + \text{gap angle} = 360^\circ$.

Use this to determine whether the 70° angle fits the gap.

In Fig. 6.12 can you explain why AOD, BOE and COF are straight lines?

Construct a regular hexagon with a sidelength 4 cm using a ruler and a compass.

Context: We can construct a regular hexagon more directly if we can construct a 120° angle using a ruler and a compass.

Q. How do we do it?

Why is $\angle\text{CAX} = 60^\circ$? Is there an equilateral triangle here?

Construct a regular hexagon of sidelength 5 cm.

How will you construct 30° and 15° angles?

Construct the following 6-pointed star. Note that it has a rotational symmetry.

Are the six triangles forming the 6 points of the star — $\Delta$AGH, $\Delta$BHI, $\Delta$CIJ, $\Delta$DJK, $\Delta$ELK, $\Delta$FLG — equilateral? Why?

[Hint: Find the angles.]

Can a $4 \times 6$ grid be tiled using multiple copies of $2 \times 1$ tiles? We are allowed to rotate a $2 \times 1$ tile and use it.

Can a $4 \times 7$ grid be tiled using $2 \times 1$ tiles?

What about a $5 \times 7$ grid?

Complete the justification.

Is an $m \times n$ grid tileable with $2 \times 1$ tiles, if both $m$ and $n$ are even? If yes, come up with a general strategy to tile it.

Is an $m \times n$ grid tileable with $2 \times 1$ tiles, if one of $m$ and $n$ is even and the other is odd? If yes, come up with a general strategy to tile it.

Is an $m \times n$ grid tileable with $2 \times 1$ tiles, if both $m$ and $n$ are odd? Give reasons.

Here is a $5 \times 3$ grid, with a unit square removed. Now, it has an even number of unit squares. Is it tileable with $2 \times 1$ tiles?

Is the following region tileable with $2 \times 1$ tiles?

Context: We are considering whether a given region can be tiled using $2 \times 1$ tiles.

Q. What about this one?

Were you able to tile this? How can we be sure that this is not tileable? Can you find another unit square that, when removed from a $5 \times 3$ grid, makes it non-tileable?

If the plain grid is tileable, is the black-and-white-grid tileable?

If the black-and-white grid is tileable, is the plain grid tileable?

Use this idea to find another unit square that, when removed from a 5 × 3 grid, makes it non-tileable?