Constructions and Tilings | FIO

Question 10

What are the other angles that can be constructed using angle bisection? Can you construct 65.5° angle?

Check your answer with HomiSolve it yourself, then let Homi check your steps and spot mistakes.
Solution

We can create new angles by bisecting existing angles or by adding and subtracting constructible angles.

Step 1 — Constructing basic angles

We can construct a 90-degree angle using a compass and ruler. Bisecting an angle means dividing it into two equal parts. Let us bisect the 90-degree angle. This gives us an angle of 45 degrees.

90÷2=4590^\circ \div 2 = \mathbf{45^\circ}

Let us bisect the 45-degree angle. This gives us an angle of 22.5 degrees.

45÷2=22.545^\circ \div 2 = \mathbf{22.5^\circ}

So, we can construct angles of 45 degrees and 22.5 degrees.

Diagram 1

Step 2 — Constructing other angles by combining

We can add constructible angles together. Let us add 90 degrees and 45 degrees.

90+45=13590^\circ + 45^\circ = \mathbf{135^\circ}

Let us add 90 degrees and 22.5 degrees.

90+22.5=112.590^\circ + 22.5^\circ = \mathbf{112.5^\circ}

Let us add 45 degrees and 22.5 degrees.

45+22.5=67.545^\circ + 22.5^\circ = \mathbf{67.5^\circ}

So, we can also construct angles of 135 degrees, 112.5 degrees, and 67.5 degrees.

Step 3 — Checking for 65.5 degrees

We need to see if 65.5 degrees can be constructed. The angles we found are 45°, 22.5°, 135°, 112.5°, and 67.5°. These angles are all multiples of 22.5 degrees or 11.25 degrees. Let us check if 65.5 degrees is a multiple of 22.5 degrees.

65.5÷22.5=1314565.5 \div 22.5 = \frac{131}{45}

This is not a whole number. So, 65.5 degrees is not a multiple of 22.5 degrees. This means we cannot make 65.5 degrees by combining these angles. Therefore, we cannot construct an angle of 65.5 degrees.

Answer

(i) The other angles that can be constructed using angle bisection are 45°, 22.5°, 135°, 112.5°, and 67.5°. (ii) No, we cannot construct an angle of 65.5°.

More questions in FIO

Q1

When constructing the perpendicular bisector, is it necessary to have the same radius for the arcs above and below XY? Explore this through construction, and then justify your answer.

[Hint 1: Any point that is of the same distance from X and Y lies on the perpendicular bisector.

Hint 2: We can draw the whole line if any two of its points are known.]

Q2

Is it necessary to construct the pairs of arcs above and below XY? Instead, can we construct both the pairs of arcs on the same side of XY? Explore this through construction, and then justify your answer.

Q3

While constructing one pair of intersecting arcs, is it necessary that we use the same radii for both of them ? Explore this through construction, and then justify your answer.

Q4

Recreate this design using only a ruler and compass —

Q5

Justify why AB in Fig. 6.4 is the perpendicular bisector.

Q6

Can you think of different methods to construct a 90° angle at a given point on a line using a rope?

Q7

Construct at least 4 different angles. Draw their bisectors.

Q8

Construct the 8-petalled figure shown in Fig. 6.5.

Q9

In Step 2 of angle bisection, if arcs of equal radius are drawn on the other side, as shown in the figure, will the line OC still be an angle bisector? Explore this through construction, and then justify your answer.

Q10

What are the other angles that can be constructed using angle bisection? Can you construct 65.5° angle?

Q11

Come up with a method to construct the angle bisector using a rope.

Q12

Construct the following figure.

How do we construct the petals so that they are of the maximum possible size within a given square?

Q13

Construct at least 4 different angles in different orientations without taking any measurement. Make a copy of all these angles.

Q14

Construct the Fig. 6.6.

Q15

Construct 4 pairs of parallel lines in different orientations.

Q16

Construct the following figure.

Q17

Use support lines in Fig. 6.11 to construct a pointed arch. Make different arches, by changing the radius of the arcs.

Q18

Make your own arch designs.

Q19

Construct the following figures:

Q20

Optical Illusion: Do you notice anything interesting about the following figure? How does this happen? Recreate this in your notebook.

Q21

Construct this figure.

[Hint: Find the angles in this figure.]

Q22

Draw a line ll and mark a point P anywhere outside the line. Construct a perpendicular to the given line ll through P.

[Hint: Find a line segment on ll whose perpendicular bisector passes through P.]

Q23

How can the tangram pieces be rearranged to form each of the following figures?

Q24

Are the following tilings possible?

← Back to Constructions and Tilings