Question 8
In the figure below, AB = AD, CB = CD.
Can you identify any pair of congruent triangles? If yes, explain why they are congruent.
Does AC divide ∠BAD and ∠BCD into two equal parts? Give reasons.

We can show two triangles are identical if their sides match up perfectly.
Step 1 — Identify equal sides
We look at the two triangles in the figure. These are triangle ABC and triangle ADC. The problem tells us some sides are equal. Side AB is equal to side AD. Side CB is equal to side CD. The line AC is part of both triangles. So, side AC is equal to side AC.
Step 2 — Apply congruence rule
We have found three pairs of equal sides. One side from triangle ABC matches one side from triangle ADC. This is true for all three sides. This means the triangles are congruent. We use the Side-Side-Side (SSS) rule. So, triangle ABC is congruent to triangle ADC.

Step 3 — Check angle bisection
We know the two triangles are congruent. This means all their matching parts are equal. We call this Corresponding Parts of Congruent Triangles (CPCT). Angle BAC is a part of triangle ABC. Angle DAC is a part of triangle ADC. These angles are matching parts. So, angle BAC is equal to angle DAC. This means AC cuts angle BAD into two equal parts. Angle BCA is a part of triangle ABC. Angle DCA is a part of triangle ADC. These angles are also matching parts. So, angle BCA is equal to angle DCA. This means AC cuts angle BCD into two equal parts.
Answer
(i) The pair of congruent triangles is triangle ABC and triangle ADC. They are congruent by the Side-Side-Side (SSS) congruence criterion because AB = AD, CB = CD, and AC = AC (common side). (ii) Yes, AC divides ∠BAD into two equal parts. (iii) Yes, AC divides ∠BCD into two equal parts.
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. Identify the corresponding vertices, sides and angles.
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(b) AB = EF, A = E, AC = ED
(c) AB = DF, B = D = 90°, AC = FE
(d) A = D, B = E, AC = DF
(e) AB = DF, B = F, AC = DE
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[Hint: AD is a transversal for these two lines. Are there any equal alternate angles?]
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