Perimeter and Area | IT

Question 13

Using 9 unit squares, solve the following.

  1. What is the smallest perimeter possible?
  2. What is the largest perimeter possible?
  3. Make a figure with a perimeter of 18 units.
  4. Can you make other shaped figures for each of the above three perimeters, or is there only one shape with that perimeter? What is your reasoning?
Question diagram 1
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Solution

The perimeter of a figure made of unit squares is the total length of its outer boundary. When squares are joined, their shared sides are no longer part of the perimeter. Each unit square has 4 sides.

Step 1 — Smallest Perimeter

To get the smallest perimeter, we arrange the 9 unit squares as compactly as possible. A square shape is the most compact. A 3×33 \times 3 square uses 9 unit squares. If 9 squares were separate, they would have 9×4=369 \times 4 = 36 sides. In a 3×33 \times 3 square, some sides are shared between adjacent squares. There are 6 horizontal shared sides. There are 6 vertical shared sides. Total shared sides = 6+6=126+6 = 12. Each shared side removes 2 unit lengths from the perimeter. So, the perimeter is 36(2×12)36 - (2 \times 12).

P=36(2×12)P = 36 - (2 \times 12)

P=3624P = 36 - 24

12 units\boxed{12 \text{ units}}

Diagram 1

Step 2 — Largest Perimeter

To get the largest perimeter, we arrange the 9 unit squares in a way that exposes as many sides as possible. This means arranging them in a long, thin strip. A 1×91 \times 9 strip is the longest possible arrangement. If 9 squares were separate, they would have 9×4=369 \times 4 = 36 sides. In a 1×91 \times 9 strip, there are 8 shared sides between the 9 squares. Each shared side removes 2 unit lengths from the perimeter. So, the perimeter is 36(2×8)36 - (2 \times 8).

P=36(2×8)P = 36 - (2 \times 8)

P=3616P = 36 - 16

20 units\boxed{20 \text{ units}}

Diagram 2

Step 3 — Figure with Perimeter of 18 Units

We need to make a figure with 9 unit squares that has a perimeter of 18 units. If 9 squares were separate, they would have 9×4=369 \times 4 = 36 sides. If the perimeter is 18 units, then 18=36(2×shared sides)18 = 36 - (2 \times \text{shared sides}). So, 2×shared sides=3618=182 \times \text{shared sides} = 36 - 18 = 18. This means the figure must have 9 shared sides. The figure shown in the diagram (the C-shaped figure) has a perimeter of 18 units.

Diagram 3

Step 4 — Other Shaped Figures

  1. For 12 units perimeter: The 3×33 \times 3 square is the only shape that gives the smallest perimeter of 12 units. Any other arrangement of 9 squares will expose more sides, leading to a larger perimeter. This is because a square is the most compact shape.

  2. For 20 units perimeter: Other shaped figures can be made with a perimeter of 20 units. For example, a 1×91 \times 9 strip of squares has a perimeter of 20 units. The 'C' shape shown in the diagram (which has 9 squares) also has a perimeter of 20 units. Many other arrangements can also achieve this perimeter.

  3. For 18 units perimeter: Other shaped figures can be made with a perimeter of 18 units. The figure shown in Step 3 is one example. We can rearrange the squares to form different shapes while keeping 9 shared sides, which results in a perimeter of 18 units.

Answer

(i) The smallest perimeter is 12 units. (ii) The largest perimeter is 20 units. (iii) A figure with a perimeter of 18 units is shown in the diagram in Step 3. (iv) Other shaped figures for 20 and 18 unit perimeters can be made by rearranging the squares. There is only one shape (a 3×33 \times 3 square) for the 12 unit perimeter.

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Q13

Using 9 unit squares, solve the following.

  1. What is the smallest perimeter possible?
  2. What is the largest perimeter possible?
  3. Make a figure with a perimeter of 18 units.
  4. Can you make other shaped figures for each of the above three perimeters, or is there only one shape with that perimeter? What is your reasoning?
Q14

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Without calculating all over again, observe, think and find out what will be the change in the perimeter if a new square is attached as shown on the right.

Q15

Experiment placing this new square at different places and think what the change in perimeter will be. Can you place the square so that the perimeter: a) increases; b) decreases; c) stays the same?

Q16

Below is the house plan of Charan. It is in a rectangular plot. Look at the plan. What do you notice?

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a. Find the missing measurements.

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Q17

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a. Find the missing measurements.

b. Find out the area of his house.

What are the dimensions of all the different rooms in Sharan's house? Compare the areas and perimeters of Sharan's house and Charan's house.

Q18

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In each figure, find the missing value of either the length of a side or the area of a region.

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