Perimeter and Area | IT

Question 14

Let's do something tricky now! We have a figure below having perimeter 24 units.

Without calculating all over again, observe, think and find out what will be the change in the perimeter if a new square is attached as shown on the right.

Question diagram 1
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Solution

When a new square is added, some old boundary lines become hidden, and some new boundary lines appear.

Step 1 — Understand the original shape

The first picture shows a cross shape. It is made of 5 small squares. Let us count the boundary lines of this cross shape. We can trace the outside edges. There are 12 outside edges. The problem tells us the perimeter is 24 units. So, each outside edge must be 2 units long. This means each small square has a side length of 2 units.

Step 2 — Observe how the new square is attached

Look at the second picture. A new small square is added. It is attached to the bottom-right part of the cross. The arrow shows it moving into place. This new square touches two parts of the original cross. It touches the bottom side of the rightmost square. It also touches the right side of the bottommost square.

Step 3 — Find the change in perimeter

When the new square is attached: Two sides of the original cross shape become hidden. These are the bottom side of the rightmost square and the right side of the bottommost square. Each of these hidden sides was part of the perimeter. So, the perimeter loses 2 sides. This means the perimeter decreases by:

2 sides×2 units/side2 \text{ sides} \times 2 \text{ units/side}

=4 units= 4 \text{ units}

The new square itself has 4 sides. Two of its sides are now hidden (its top side and its left side). Two of its sides are now part of the new perimeter (its bottom side and its right side). So, the new square adds 2 new sides to the perimeter. This means the perimeter increases by:

2 sides×2 units/side2 \text{ sides} \times 2 \text{ units/side}

=4 units= 4 \text{ units}

Step 4 — Calculate the total change

The perimeter decreased by 4 units because old sides became hidden. The perimeter increased by 4 units because new sides appeared. Let us find the total change.

Total change=IncreaseDecrease\text{Total change} = \text{Increase} - \text{Decrease}

=4 units4 units= 4 \text{ units} - 4 \text{ units}

=0 units= 0 \text{ units}

stays the same\boxed{\text{stays the same}}

Diagram 1

Answer

(i) stays the same.

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Q5

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Q6

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Q7

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Q8

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Q9

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  • Can you see some relationship between the blue rectangle and the yellow triangle and their areas? Write the relationship here.
Q10

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Q11

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Q12

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Q13

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  1. What is the smallest perimeter possible?
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Q14

Let's do something tricky now! We have a figure below having perimeter 24 units.

Without calculating all over again, observe, think and find out what will be the change in the perimeter if a new square is attached as shown on the right.

Q15

Experiment placing this new square at different places and think what the change in perimeter will be. Can you place the square so that the perimeter: a) increases; b) decreases; c) stays the same?

Q16

Below is the house plan of Charan. It is in a rectangular plot. Look at the plan. What do you notice?

Some of the measurements are given.

a. Find the missing measurements.

b. Find out the area of his house.

Q17

Now, find out the missing dimensions and area of Sharan's home. Below is the plan:

Some of the measurements are given.

a. Find the missing measurements.

b. Find out the area of his house.

What are the dimensions of all the different rooms in Sharan's house? Compare the areas and perimeters of Sharan's house and Charan's house.

Q18

Area Maze Puzzles

In each figure, find the missing value of either the length of a side or the area of a region.

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