Introduction to Linear Polynomials | Exercise 2.4

Question 1

Suppose a plant has height 1.75 feet and it grows by 0.5 feet each month.

(i) Find the height after 7 months.

(ii) Make a table of values for tt varying from 0 to 10 months and show how the height, hh, increases every month.

(iii) Find an expression that relates hh and tt, and explain why it represents linear growth.

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Solution

We will find the plant's height using its initial height and monthly growth.

Step 1 — Calculate height after 7 months

Let's find how much the plant grows in 7 months. The plant grows by 0.5 feet each month.

Growth in 7 months=0.5×7\text{Growth in 7 months} = 0.5 \times 7

=3.5 feet= 3.5 \text{ feet}

Now, we add this growth to the initial height. The initial height is 1.75 feet.

Height after 7 months=1.75+3.5\text{Height after 7 months} = 1.75 + 3.5

5.25 feet\boxed{5.25 \text{ feet}}

Step 2 — Create a table of values

Let's make a table showing height hh for months tt from 0 to 10. The height starts at 1.75 feet. It increases by 0.5 feet every month.

| t (months) | h (feet) | | :--------: | :------: | | 0 | 1.75 | | 1 | 2.25 | | 2 | 2.75 | | 3 | 3.25 | | 4 | 3.75 | | 5 | 4.25 | | 6 | 4.75 | | 7 | 5.25 | | 8 | 5.75 | | 9 | 6.25 | | 10 | 6.75 |

Step 3 — Find the expression and explain linear growth

Let hh be the height of the plant. Let tt be the number of months. The initial height is 1.75 feet. The plant grows by 0.5 feet per month.

So, the height hh after tt months is:

h=1.75+0.5th = 1.75 + 0.5t

This expression shows linear growth. The height increases by a constant amount (0.5 feet) every month. This constant rate of change is a key feature of linear relationships.

Answer

(i) The height after 7 months is 5.25 feet. (ii) The table of values is: | t (months) | h (feet) | | :--------: | :------: | | 0 | 1.75 | | 1 | 2.25 | | 2 | 2.75 | | 3 | 3.25 | | 4 | 3.75 | | 5 | 4.25 | | 6 | 4.75 | | 7 | 5.25 | | 8 | 5.75 | | 9 | 6.25 | | 10 | 6.75 | (iii) The expression is h=1.75+0.5th = 1.75 + 0.5t. It represents linear growth because the height increases by a constant amount of 0.5 feet each month.

More questions in Exercise 2.4

Q1

Suppose a plant has height 1.75 feet and it grows by 0.5 feet each month.

(i) Find the height after 7 months.

(ii) Make a table of values for tt varying from 0 to 10 months and show how the height, hh, increases every month.

(iii) Find an expression that relates hh and tt, and explain why it represents linear growth.

Q2

A mobile phone is bought for ₹10,000. Its value decreases by ₹800 every year.

(i) Find the value of the phone after 3 years.

(ii) Make a table of values for tt varying from 0 to 8 years and show how the value of the phone, vv, depreciates with time.

(iii) Find an expression that relates vv and tt, and explain why it represents linear decay.

Q3

The initial population of a village is 750. Every year, 50 people move from a nearby city to the village.

(i) Find the population of the village after 6 years.

(ii) Make a table of values for tt varying from 0 to 10 years and show how the population, PP, increases every year.

(iii) Find an expression that relates PP and tt, and explain why it represents linear growth.

Q4

A telecom company charges ₹600 for a certain recharge scheme. This prepaid balance is reduced by ₹15 each day after the recharge.

(i) Write an equation that models the remaining balance b(x)b(x) after using the scheme for xx days. Explain why it represents linear decay.

(ii) After how many days will the balance run out?

(iii) Make a table of values for xx varying from 1 to 10 days and show how the balance b(x)b(x) reduces with time.

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