Exploring Algebraic Identities | Exercise 4.3

Question 3

Expand the following using the identity (a+b+c)2=a2+b2+c2+2ab+2bc+2ca(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca:

(i) (p+3q+7r)2(p + 3q + 7r)^2

(ii) (3x2y+4z)2(3x - 2y + 4z)^2

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Solution

We will use the given algebraic identity to expand the expressions.

Step 1 — Expanding (p+3q+7r)2(p + 3q + 7r)^2

Let's identify the terms. Here, a=p\mathbf{a = p}, b=3q\mathbf{b = 3q}, and c=7r\mathbf{c = 7r}. We use the identity (a+b+c)2=a2+b2+c2+2ab+2bc+2ca(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca.

(p+3q+7r)2=(p)2+(3q)2+(7r)2+2(p)(3q)+2(3q)(7r)+2(p)(7r)(p + 3q + 7r)^2 = (p)^2 + (3q)^2 + (7r)^2 + 2(p)(3q) + 2(3q)(7r) + 2(p)(7r)

=p2+9q2+49r2+6pq+42qr+14pr= p^2 + 9q^2 + 49r^2 + 6pq + 42qr + 14pr

p2+9q2+49r2+6pq+42qr+14pr\boxed{p^2 + 9q^2 + 49r^2 + 6pq + 42qr + 14pr}

Diagram 2

Step 2 — Expanding (3x2y+4z)2(3x - 2y + 4z)^2

Let's rewrite the expression first. We can write (3x2y+4z)2(3x - 2y + 4z)^2 as [3x+(2y)+4z]2[3x + (-2y) + 4z]^2. Now, let's identify the terms. Here, a=3x\mathbf{a = 3x}, b=2y\mathbf{b = -2y}, and c=4z\mathbf{c = 4z}. We use the identity (a+b+c)2=a2+b2+c2+2ab+2bc+2ca(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca.

(3x2y+4z)2=(3x)2+(2y)2+(4z)2+2(3x)(2y)+2(2y)(4z)+2(3x)(4z)(3x - 2y + 4z)^2 = (3x)^2 + (-2y)^2 + (4z)^2 + 2(3x)(-2y) + 2(-2y)(4z) + 2(3x)(4z)

=9x2+4y2+16z212xy16yz+24xz= 9x^2 + 4y^2 + 16z^2 - 12xy - 16yz + 24xz

9x2+4y2+16z212xy16yz+24xz\boxed{9x^2 + 4y^2 + 16z^2 - 12xy - 16yz + 24xz}

<DIAGRAM: No diagram needed for this algebraic expansion.>

Answer

(i) p2+9q2+49r2+6pq+42qr+14prp^2 + 9q^2 + 49r^2 + 6pq + 42qr + 14pr (ii) 9x2+4y2+16z212xy16yz+24xz9x^2 + 4y^2 + 16z^2 - 12xy - 16yz + 24xz

More questions in Exercise 4.3

Q1

Find the following squares using one of the above identities. Determine which of these identities will make these calculations easier.

(i) 1172117^2

(ii) 78278^2

(iii) 1982198^2

(iv) 2142214^2

(v) 110421104^2

(vi) 112021120^2

Q2

Factor using suitable identities:

(i) 16y224y+916y^2 - 24y + 9

(ii) 94s2+6st+4t2\frac{9}{4}s^2 + 6st + 4t^2

(iii) m29+mk3+k24+3nk+2mn+9n2\frac{m^2}{9} + \frac{mk}{3} + \frac{k^2}{4} + 3nk + 2mn + 9n^2

(iv) p2162+16p2\frac{p^2}{16} - 2 + \frac{16}{p^2}

(v) 9a2+4b2+c212ab+6ac4bc9a^2 + 4b^2 + c^2 - 12ab + 6ac - 4bc

Q3

Expand the following using the identity (a+b+c)2=a2+b2+c2+2ab+2bc+2ca(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca:

(i) (p+3q+7r)2(p + 3q + 7r)^2

(ii) (3x2y+4z)2(3x - 2y + 4z)^2

Q4

Is this an identity?

(a+bc)2+(ab+c)2+(abc)2=2a2+2b2+2c2(a + b - c)^2 + (a - b + c)^2 + (a - b - c)^2 = 2a^2 + 2b^2 + 2c^2.

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