Exploring Algebraic Identities

25 questions · step-by-step solutions

Get free step-by-step NCERT solutions for Class 9 Maths Exploring Algebraic Identities (Chapter 4). All 25 questions across 6 exercises are solved with clear reasoning, following the CBSE 2026–27 syllabus. Work through each solution to understand the method, not just the final answer.

Exercise 4.1

Question 1

Using the identity (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2, expand the following:

(i) (7x+4y)2(7x + 4y)^2

(ii) (75x+32y)2\left(\frac{7}{5}x + \frac{3}{2}y\right)^2

(iii) (2.5p+1.5q)2(2.5p + 1.5q)^2

(iv) (34s+8t)2\left(\frac{3}{4}s + 8t\right)^2

(v) (x+12y)2\left(x + \frac{1}{2y}\right)^2

(vi) (1x+1y)2\left(\frac{1}{x} + \frac{1}{y}\right)^2

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Question 2

Using the same identity, find the values of the following:

(i) (64)2(64)^2

(ii) (105)2(105)^2

(iii) (205)2(205)^2

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Exercise 4.2

Question 1

Factor completely:

(i) 9x2+24xy+16y29x^2 + 24xy + 16y^2

(ii) 4s2+20st+25t24s^2 + 20st + 25t^2

(iii) 49x2+28xy+4y249x^2 + 28xy + 4y^2

(iv) 64p2+323pq+49q264p^2 + \frac{32}{3}pq + \frac{4}{9}q^2

*(v) 3a2+4ab+43b23a^2 + 4ab + \frac{4}{3}b^2

*(vi) 95s2+6sv+5v2\frac{9}{5}s^2 + 6sv + 5v^2

(Hint: 2 was taken out as a common factor in Example 7. Is it possible to do something similar in Exercises (v) and (vi) above?)

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Question 2

Find the values of the following using the identity (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2.

(i) (79)2(79)^2

(ii) (193)2(193)^2

(iii) (299)2(299)^2

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Exercise 4.3

Question 1

Find the following squares using one of the above identities. Determine which of these identities will make these calculations easier.

(i) 1172117^2

(ii) 78278^2

(iii) 1982198^2

(iv) 2142214^2

(v) 110421104^2

(vi) 112021120^2

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Question 2

Factor using suitable identities:

(i) 16y224y+916y^2 - 24y + 9

(ii) 94s2+6st+4t2\frac{9}{4}s^2 + 6st + 4t^2

(iii) m29+mk3+k24+3nk+2mn+9n2\frac{m^2}{9} + \frac{mk}{3} + \frac{k^2}{4} + 3nk + 2mn + 9n^2

(iv) p2162+16p2\frac{p^2}{16} - 2 + \frac{16}{p^2}

(v) 9a2+4b2+c212ab+6ac4bc9a^2 + 4b^2 + c^2 - 12ab + 6ac - 4bc

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Question 3

Expand the following using the identity (a+b+c)2=a2+b2+c2+2ab+2bc+2ca(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca:

(i) (p+3q+7r)2(p + 3q + 7r)^2

(ii) (3x2y+4z)2(3x - 2y + 4z)^2

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Question 4

Is this an identity?

(a+bc)2+(ab+c)2+(abc)2=2a2+2b2+2c2(a + b - c)^2 + (a - b + c)^2 + (a - b - c)^2 = 2a^2 + 2b^2 + 2c^2.

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Exercise 4.4

Question 1

Fill in the blanks to complete the following identities:

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Question 2

Select and use the identity that will help you find the following products without multiplying directly:

(i) (41)2(41)^2

(ii) (27)2(27)^2

(iii) (23×17)(23 \times 17)

(iv) (135)2(135)^2

(v) (97)2(97)^2

(vi) (18×29)(18 \times 29)

(vii) (34×43)(34 \times 43)

(viii) (205)2(205)^2

View Solution
Question 3

Factor the following:

(i) 9a2+b2+4c26ab+12ac4bc9a^2 + b^2 + 4c^2 - 6ab + 12ac - 4bc

(ii) 16s2+25t240st16s^2 + 25t^2 - 40st

(iii) r2r42r^2 - r - 42

(iv) 49g2+14gh+h249g^2 + 14gh + h^2

(v) 64u2+121v2+4w2176uv32uw+44vw64u^2 + 121v^2 + 4w^2 - 176uv - 32uw + 44vw

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Exercise 4.5

Question 1

Simplify the following rational expressions assuming that the expressions in the denominators are not equal to zero:

(i) 3p23pq18q2p2+3pq10q2\frac{3p^2 - 3pq - 18q^2}{p^2 + 3pq - 10q^2}

(ii) n33n2m+3nm2m35m210mn+5n2\frac{n^3 - 3n^2m + 3nm^2 - m^3}{5m^2 - 10mn + 5n^2}

(iii) w3v3+x3+3wvxw2+v2+x22wv2vx+2wx\frac{w^3 - v^3 + x^3 + 3wvx}{w^2 + v^2 + x^2 - 2wv - 2vx + 2wx}

(iv) 4y220yz+25z2(25z24y2)\frac{4y^2 - 20yz + 25z^2}{(25z^2 - 4y^2)}

(v) (x2+x6)(x27x+12)(x26x+8)(x29)\frac{(x^2 + x - 6)(x^2 - 7x + 12)}{(x^2 - 6x + 8)(x^2 - 9)}

(vi) p416p24p+4\frac{p^4 - 16}{p^2 - 4p + 4}

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EOT

Question 1

Use suitable identities to find the following products:

(i) (3x+4)2(-3x + 4)^2

(ii) (2s+7)(2s7)(2s + 7)(2s - 7)

(iii) (p2+12)(p212)\left(p^2 + \frac{1}{2}\right)\left(p^2 - \frac{1}{2}\right)

(iv) (2n+7)(2n7)(2n + 7)(2n - 7)

(v) (s2t)(s2+2st+4t2)(s - 2t)(s^2 + 2st + 4t^2)

(vi) (12r4r)2\left(\frac{1}{2r} - 4r\right)^2

(vii) (3m+4kl)2(-3m + 4k - l)^2

(viii) (x13y)3\left(x - \frac{1}{3}y\right)^3

(ix) (72k23m)3\left(\frac{7}{2}k - \frac{2}{3}m\right)^3

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Question 2

Find the values using suitable identities:

(i) 17×2117 \times 21

(ii) 104×96104 \times 96

(iii) 24×1624 \times 16

(iv) 1473147^3

(v) 1993199^3

(vi) 1273127^3

(vii) (107)3(-107)^3

(viii) (299)3(-299)^3

View Solution
Question 3

Factor the following algebraic expressions:

(i) 4y2+1+116y24 y^2 + 1 + \frac{1}{16 y^2}

(ii) 9m2125n29m^2 - \frac{1}{25n^2}

(iii) 27b3164b327b^3 - \frac{1}{64b^3}

(iv) x2+5x6+16x^2 + \frac{5x}{6} + \frac{1}{6}

(v) 27u3112527u25+9u2527u^3 - \frac{1}{125} - \frac{27u^2}{5} + \frac{9u}{25}

(vi) 64y3+1125z364y^3 + \frac{1}{125}z^3

(vii) p3+27q3+r39pqrp^3 + 27q^3 + r^3 - 9pqr

(viii) 9m212m+49m^2 - 12m + 4

(ix) 9x383y3+z33+6xyz9x^3 - \frac{8}{3}y^3 + \frac{z^3}{3} + 6xyz

(x) 4x2+9y2+36z2+12xz+36yz+24xy4x^2 + 9y^2 + 36z^2 + 12xz + 36yz + 24xy

(xi) 27u312169u22+u427u^3 - \frac{1}{216} - \frac{9u^2}{2} + \frac{u}{4}

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Question 4

Simplify the following:

(i) 4x2+4x+14x21\frac{4x^2 + 4x + 1}{4x^2 - 1}

(ii) 9(3a324b3)9a236b2\frac{9(3a^3 - 24b^3)}{9a^2 - 36b^2}

(iii) s3+125t3s22st35t2\frac{s^3 + 125t^3}{s^2 - 2st - 35t^2}

Note: Assume that the denominators are not equal to 0.

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Question 5

Find possible expressions for the length and breadth of each of the following rectangles whose areas are given by the following expressions in square units.

(i) 25a230ab+9b225a^2 - 30ab + 9b^2

(ii) 36s249t236s^2 - 49t^2

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Question 6

Find possible expressions for the length, breadth, and heights of each of the following cuboids whose volumes are given by the following expressions in cubic units.

(i) 6a224b26a^2 - 24b^2

(ii) 3ps215ps+12p3ps^2 - 15ps + 12p

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Question 7

The village playground is shaped as a square of side 40 metres. A path of width ss metres is created around the playground for people to walk. Find an expression for the area of the path in terms of ss.

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Question 8

If a number plus its reciprocal equals 103\frac{10}{3}, find the number.

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Question 9

A rectangular pool has area 2x2+7x+32x^2 + 7x + 3 square hastas. If its width is 2x+12x + 1 hastas, find its length. Hasta was a unit used to measure length.

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Question 10

If both x2x - 2 and x12x - \frac{1}{2} are factors of px2+5x+rpx^2 + 5x + r, show that p=rp = r.

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Question 11

If a+b+c=5a + b + c = 5 and ab+bc+ca=10ab + bc + ca = 10, then prove that a3+b3+c33abc=25a^3 + b^3 + c^3 - 3abc = -25.

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Question 12

By factoring the expression, check that n3nn^3 - n is always divisible by 6 for all natural numbers nn. Give reasons.

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Question 13

Find the value of

(i) x3+y312xy+64x^3 + y^3 - 12xy + 64, when x+y=4x + y = -4

(ii) x38y336xy216x^3 - 8y^3 - 36xy - 216, when x=2y+6x = 2y + 6

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Frequently asked questions

Common questions about Class 9 Maths Exploring Algebraic Identities solutions.

How many questions are there in Class 9 Maths Exploring Algebraic Identities?

Exploring Algebraic Identities (Chapter 4) in Class 9 Maths has 25 questions across 6 exercises. Every question is solved step by step on this page.

Are these Exploring Algebraic Identities solutions based on the latest NCERT syllabus?

Yes. These solutions follow the current CBSE 2026–27 syllabus and the latest NCERT textbook for Class 9 Maths. If the exercises change, the solutions here are updated to match.

How should I use these Exploring Algebraic Identities solutions?

Try each question yourself first, then read the step-by-step solution to see where your approach diverged. Focus on understanding the method behind each step, not just the final answer.