Rational Numbers | FIO

Question 1

Which of the following numbers are not perfect squares?

(i) 2032 (ii) 2048 (iii) 1027 (iv) 1089

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Solution

We can check if a number is a perfect square by looking at its last digit or by finding its square root.

Step 1 — Understanding Perfect Squares

A perfect square is a number you get by multiplying an integer by itself. For example, 2525 is a perfect square because 5×5=255 \times 5 = 25. Also, 100100 is a perfect square because 10×10=10010 \times 10 = 100.

Step 2 — Checking Unit Digits of Perfect Squares

The unit digit is the last digit of any number. Let us look at the unit digits of the first few perfect squares: 12=11^2 = 1 22=42^2 = 4 32=93^2 = 9 42=164^2 = 16 (ends in 6) 52=255^2 = 25 (ends in 5) 62=366^2 = 36 (ends in 6) 72=497^2 = 49 (ends in 9) 82=648^2 = 64 (ends in 4) 92=819^2 = 81 (ends in 1) 102=10010^2 = 100 (ends in 0) We can see that perfect squares can only end in the digits 0, 1, 4, 5, 6, or 9. If a number ends in 2, 3, 7, or 8, it cannot be a perfect square.

Step 3 — Applying the Unit Digit Check

Let us check each number given in the question using this rule.

(i) For 2032: The unit digit of 2032 is 2. Since a perfect square cannot end in 2, 2032 is not a perfect square.

(ii) For 2048: The unit digit of 2048 is 8. Since a perfect square cannot end in 8, 2048 is not a perfect square.

(iii) For 1027: The unit digit of 1027 is 7. Since a perfect square cannot end in 7, 1027 is not a perfect square.

(iv) For 1089: The unit digit of 1089 is 9. A number ending in 9 can be a perfect square. So, we need to check this number further to confirm.

Step 4 — Finding the Square Root for 1089

We need to find if there is an integer xx such that x2=1089x^2 = 1089. Since 1089 is a 4-digit number, its square root will be a 2-digit number. We know that 302=90030^2 = 900. We also know that 402=160040^2 = 1600. So, the square root of 1089 must be between 30 and 40. The unit digit of 1089 is 9. This means the unit digit of its square root must be either 3 (because 32=93^2=9) or 7 (because 72=497^2=49). So, the possible square roots are 33 or 37. Let us try squaring 33: 33×3333 \times 33 =(30+3)×(30+3)= (30 + 3) \times (30 + 3) =30×30+30×3+3×30+3×3= 30 \times 30 + 30 \times 3 + 3 \times 30 + 3 \times 3 =900+90+90+9= 900 + 90 + 90 + 9 =1080+9= 1080 + 9

1089\boxed{1089} Since 332=108933^2 = 1089, the number 1089 is a perfect square.

Answer

(i) 2032 is not a perfect square. (ii) 2048 is not a perfect square. (iii) 1027 is not a perfect square.

More questions in FIO

Q1

Which of the following numbers are not perfect squares?

(i) 2032 (ii) 2048 (iii) 1027 (iv) 1089

Q2

Which one among 64264^2, 1082108^2, 2922292^2, 36236^2 has last digit 4?

Q3

Given 1252=15625125^2 = 15625, what is the value of 1262126^2?

(i) 15625 + 126

(ii) 15625+26215625 + 26^2

(iii) 15625 + 253

(iv) 15625 + 251

(v) 15625+51215625 + 51^2

Q4

Find the length of the side of a square whose area is 441 m2441\text{ m}^2.

Q5

Find the smallest square number that is divisible by each of the following numbers: 4, 9, and 10.

Q6

Find the smallest number by which 9408 must be multiplied so that the product is a perfect square. Find the square root of the product.

Q7

How many numbers lie between the squares of the following numbers?

(i) 16 and 17 (ii) 99 and 100

Q8

In the following pattern, fill in the missing numbers:

12+22+22=321^2 + 2^2 + 2^2 = 3^2 22+32+62=722^2 + 3^2 + 6^2 = 7^2 32+42+122=1323^2 + 4^2 + 12^2 = 13^2

(a) 42+52+202=()24^2 + 5^2 + 20^2 = (\underline{\quad})^2

(b) 92+102+()2=()29^2 + 10^2 + (\underline{\quad})^2 = (\underline{\quad})^2

Q9

How many tiny squares are there in the following picture? Write the prime factorisation of the number of tiny squares.

Q10

Find the cube roots of 27000 and 10648.

Q11

What number will you multiply by 1323 to make it a cube number?

Q12

State true or false. Explain your reasoning.

(i) The cube of any odd number is even.

(ii) There is no perfect cube that ends with 8.

(iii) The cube of a 2-digit number may be a 3-digit number.

(iv) The cube of a 2-digit number may have seven or more digits.

(v) Cube numbers have an odd number of factors.

Q13

You are told that 1331 is a perfect cube. Can you guess without factorisation what its cube root is? Similarly, guess the cube roots of 4913, 12167, and 32768.

Q14

Which of the following is the greatest? Explain your reasoning.

(i) 67366367^3 - 66^3

(ii) 43342343^3 - 42^3

(iii) 67266267^2 - 66^2

(iv) 43242243^2 - 42^2

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