Divisibility and Multiples | FIO

Question 8

Find a number that leaves a remainder of 2 when divided by 3, a remainder of 3 when divided by 4, and a remainder of 4 when divided by 5. What is the smallest such number? Can you give a simple explanation of why it is the smallest?

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Solution

We will find the number by looking for a pattern in the remainders.

Step 1 — Write down the conditions

Let the number we are looking for be NN. The first condition is: NN leaves a remainder of 2 when divided by 3. This means N=3k+2N = 3k + 2, for some whole number kk. The second condition is: NN leaves a remainder of 3 when divided by 4. This means N=4m+3N = 4m + 3, for some whole number mm. The third condition is: NN leaves a remainder of 4 when divided by 5. This means N=5p+4N = 5p + 4, for some whole number pp. We can write these conditions using modular arithmetic. Modular arithmetic describes remainders. N2(mod3)N \equiv 2 \pmod{3} N3(mod4)N \equiv 3 \pmod{4} N4(mod5)N \equiv 4 \pmod{5}

Step 2 — Find a common pattern

Let us look closely at the remainders and the divisors. For the first condition, the remainder is 2 and the divisor is 3. Notice 32=13 - 2 = 1. For the second condition, the remainder is 3 and the divisor is 4. Notice 43=14 - 3 = 1. For the third condition, the remainder is 4 and the divisor is 5. Notice 54=15 - 4 = 1. In all cases, the remainder is exactly one less than the divisor. This means N+1N+1 will be perfectly divisible by 3, 4, and 5. So, N+1N+1 must be a common multiple of 3, 4, and 5.

Step 3 — Calculate the Least Common Multiple

We need the smallest multiple of 3, 4, and 5. This smallest number is called the Least Common Multiple (LCM). First, we write the prime factors of each number. 3 is a prime number. 4 can be written as 2×2=222 \times 2 = 2^2. 5 is a prime number. To find the LCM, we use the highest power of each prime factor.

LCM(3,4,5)=31×22×51LCM(3, 4, 5) = 3^1 \times 2^2 \times 5^1

=3×4×5= 3 \times 4 \times 5

=60= 60

LCM(3,4,5)=60\boxed{LCM(3, 4, 5) = 60}

Step 4 — Find the smallest number N

We found N+1N+1 is a common multiple of 3, 4, and 5. For the smallest NN, N+1N+1 must be the smallest common multiple. The smallest common multiple is the LCM, which is 60. So, we have:

N+1=60N+1 = 60

Now, we can find NN by subtracting 1 from both sides.

N=601N = 60 - 1

N=59N = 59

N=59\boxed{N = 59}

This is the smallest such number. It is smallest because we used the Least Common Multiple for N+1N+1. Any other common multiple is larger than 60. This would make NN larger.

Answer

(i) The smallest such number is 59. (ii) It is the smallest because N+1N+1 is the LCM of 3, 4, and 5. The LCM is 60. Any other common multiple is larger. This makes NN larger.

More questions in FIO

Q1

The sum of four consecutive numbers is 34. What are these numbers?

Q2

Suppose pp is the greatest of five consecutive numbers. Describe the other four numbers in terms of pp.

Q3

For each statement below, determine whether it is always true, sometimes true, or never true. Explain your answer. Mention examples and non-examples as appropriate. Justify your claim using algebra.

(i) The sum of two even numbers is a multiple of 3.

(ii) If a number is not divisible by 18, then it is also not divisible by 9.

(iii) If two numbers are not divisible by 6, then their sum is not divisible by 6.

(iv) The sum of a multiple of 6 and a multiple of 9 is a multiple of 3.

(v) The sum of a multiple of 6 and a multiple of 3 is a multiple of 9.

Q4

Find a few numbers that leave a remainder of 2 when divided by 3 and a remainder of 2 when divided by 4. Write an algebraic expression to describe all such numbers.

Q5

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Q6

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Q7

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(i) 4779 + 661

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Q8

Find a number that leaves a remainder of 2 when divided by 3, a remainder of 3 when divided by 4, and a remainder of 4 when divided by 5. What is the smallest such number? Can you give a simple explanation of why it is the smallest?

Q9

Find, without dividing, whether the following numbers are divisible by 9.

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Q10

Find the smallest multiple of 9 with no odd digits.

Q11

Find the multiple of 9 that is closest to the number 6000.

Q12

How many multiples of 9 are there between the numbers 4300 and 4400?

Q13

The digital root of an 8-digit number is 5. What will be the digital root of 10 more than that number?

Q14

Write any number. Generate a sequence of numbers by repeatedly adding 11. What would be the digital roots of this sequence of numbers? Share your observations.

Q15

What will be the digital root of the number 9a+36b+139a + 36b + 13?

Q16

Make conjectures by examining if there are any patterns or relations between (i) the parity of a number and its digital root. (ii) the digital root of a number and the remainder obtained when the number is divided by 3 or 9.

Q17

If 31z5 is a multiple of 9, where z is a digit, what is the value of z? Explain why there are two answers to this problem.

Q18

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Q19

When is the sum of two multiples of 3, a multiple of 6 and when is it not? Explain the different possible cases, and generalise the pattern.

Q20

Sreelatha says, "I have a number that is divisible by 9. If I reverse its digits, it will still be divisible by 9".

(i) Examine if her conjecture is true for any multiple of 9.

(ii) Are any other digit shuffles possible such that the number formed is still a multiple of 9?

Q21

If 48a23b is a multiple of 18, list all possible pairs of values for a and b.

Q22

If 3p7q83p7q8 is divisible by 44, list all possible pairs of values for pp and qq.

Q23

Find three consecutive numbers such that the first number is a multiple of 2, the second number is a multiple of 3, and the third number is a multiple of 4.

Are there more such numbers? How often do they occur?

Q24

Write five multiples of 36 between 45,000 and 47,000. Share your approach with the class.

Q25

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Q26

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Q27

Deepak claims, "There are some multiples of 11 which, when doubled, are still multiples of 11. But other multiples of 11 don't remain multiples of 11 when doubled". Examine if his conjecture is true; explain your conclusion.

Q28

Determine whether the statements below are 'Always True', 'Sometimes True', or 'Never True'. Explain your reasoning.

(i) The product of a multiple of 6 and a multiple of 3 is a multiple of 9. (ii) The sum of three consecutive even numbers will be divisible by 6. (iii) If abcdefabcdef is a multiple of 6, then badcefbadcef will be a multiple of 6. (iv) 8(7b3)4(11b+1)8 (7b - 3) - 4 (11b + 1) is a multiple of 12.

Q29

Choose any 3 numbers. When is their sum divisible by 3? Explore all possible cases and generalise.

Q30

Is the product of two consecutive integers always multiple of 2? Why? What about the product of these consecutive integers? Is it always a multiple of 6? Why or why not? What can you say about the product of 4 consecutive integers? What about the product of five consecutive integers?

Q31

Solve the cryptarithms —

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Q32

Which of the following Venn diagrams captures the relationship between the multiples of 4, 8, and 32?

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