Operations with Integers | FIO

Question 20

Find the values of:

(a) (32×(18))÷((36))(32 \times (-18)) \div ((-36))

(b) (32)÷((36)×(18))(32) \div ((-36) \times (-18))

(c) (25×(12))÷((45)×(27))(25 \times (-12)) \div ((45) \times (-27))

(d) (280×(7))÷((8)×(35))(280 \times (-7)) \div ((-8) \times (-35))

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Solution

We will solve each part by following the order of operations, performing multiplication and division of integers.

Step 1 — Solving part (a)

First, we multiply the numbers inside the first bracket. We multiply 32 by -18. A positive number multiplied by a negative number gives a negative product.

32×(18)=57632 \times (-18) = -576

Next, we divide this result by -36. A negative number divided by a negative number gives a positive result.

576÷(36)-576 \div (-36)

=16= 16

16\boxed{\text{16}}

Diagram 1

Step 2 — Solving part (b)

First, we multiply the numbers inside the second bracket. We multiply -36 by -18. A negative number multiplied by a negative number gives a positive product.

(36)×(18)=648(-36) \times (-18) = 648

Next, we divide 32 by this result. We divide 32 by 648. This will give us a fraction.

32÷64832 \div 648

=32648= \frac{32}{648}

We simplify the fraction by dividing both numbers by their common factors. Both 32 and 648 are divisible by 2.

=16324= \frac{16}{324}

Again, both 16 and 324 are divisible by 2.

=8162= \frac{8}{162}

Once more, both 8 and 162 are divisible by 2.

=481= \frac{4}{81}

There are no more common factors for 4 and 81.

481\boxed{\frac{4}{81}}

Step 3 — Solving part (c)

First, we calculate the product in the numerator. We multiply 25 by -12. A positive number multiplied by a negative number gives a negative product.

25×(12)=30025 \times (-12) = -300

Next, we calculate the product in the denominator. We multiply 45 by -27. A positive number multiplied by a negative number gives a negative product.

45×(27)=121545 \times (-27) = -1215

Now, we divide the first result by the second result. We divide -300 by -1215. A negative number divided by a negative number gives a positive result.

300÷(1215)-300 \div (-1215)

=3001215= \frac{300}{1215}

We simplify the fraction. Both numbers are divisible by 5.

=60243= \frac{60}{243}

Both 60 and 243 are divisible by 3.

=2081= \frac{20}{81}

There are no more common factors for 20 and 81.

2081\boxed{\frac{20}{81}}

Step 4 — Solving part (d)

First, we calculate the product in the numerator. We multiply 280 by -7. A positive number multiplied by a negative number gives a negative product.

280×(7)=1960280 \times (-7) = -1960

Next, we calculate the product in the denominator. We multiply -8 by -35. A negative number multiplied by a negative number gives a positive product.

(8)×(35)=280(-8) \times (-35) = 280

Now, we divide the first result by the second result. We divide -1960 by 280. A negative number divided by a positive number gives a negative result.

1960÷280-1960 \div 280

=7= -7

-7\boxed{\text{-7}}

Answer

(a) 16 (b) 481\mathbf{\frac{4}{81}} (c) 2081\mathbf{\frac{20}{81}} (d) -7

More questions in FIO

Q1

Let us try to find a few more pairs of numbers from their sums and differences:

(a) Sum = 27, Difference = 9

(b) Sum = 4, Difference = 12

(c) Sum = 0, Difference = 10

(d) Sum = 0, Difference = -10

(e) Sum = -7, Difference = -1

(f) Sum = -7, Difference = -13

Q2

Using the token interpretation, find the values of:

(a) 3×(2)3 \times (-2)

(b) (5)×(2)(-5) \times (-2)

(c) (4)×(1)(-4) \times (-1)

(d) (7)×3(-7) \times 3

Q3

If 123×456=56088123 \times 456 = 56088, without calculating, find the value of:

(a) (123)×456(-123) \times 456

(b) (123)×(456)(-123) \times (-456)

(c) (123)×(456)(123) \times (-456)

Q4

Try to frame a simple rule to multiply two integers.

Consider the numbers represented by the following tokens in the diagram:

Q5

Find the following products.

(a) 4×(3)4 \times (-3)

(b) (6)×(3)(-6) \times (-3)

(c) (5)×(1)(-5) \times (-1)

(d) (8)×4(-8) \times 4

(e) (9)×10(-9) \times 10

(f) 10×(17)10 \times (-17)

Q6

Find the values of:

(a) 14×(15)14 \times (-15)

(b) 16×(5)-16 \times (-5)

(c) 36÷(18)36 \div (-18)

(d) (46)÷(23)(-46) \div (-23)

Q7

A freezing process requires that the room temperature be lowered from 32C32^\circ\text{C} at the rate of 5C5^\circ\text{C} every hour. What will be the room temperature 10 hours after the process begins?

Q8

A cement company earns a profit of ₹8 per bag of white cement sold and a loss of ₹5 per bag of grey cement sold. [Represent the profit/loss as integers.]

(a) The company sells 3,000 bags of white cement and 5,000 bags of grey cement in a month. What is its profit or loss? (b) If the number of bags of grey cement sold is 6,400 bags, what is the number of bags of white cement the company must sell to have neither profit nor loss?

Q9

Replace the blank with an integer to make a true statement.

(a) (3)×=27(-3) \times \underline{\quad\quad} = 27

(b) 5×=(35)5 \times \underline{\quad\quad} = (-35)

(c) ×(8)=(56)\underline{\quad\quad} \times (-8) = (-56)

(d) ×(12)=132\underline{\quad\quad} \times (-12) = 132

(e) ÷(8)=7\underline{\quad\quad} \div (-8) = 7

(f) ÷12=11\underline{\quad\quad} \div 12 = -11

Q10

Find the values of the following expressions: (a) (5)×(18+(3))(-5) \times (18 + (-3)) (b) (7)×4×(1)(-7) \times 4 \times (-1) (c) (2)×(1)×(5)×(3)(-2) \times (-1) \times (-5) \times (-3)

Q11

Find the values of the following expressions:

(a) (27)÷9(-27) \div 9

(b) 84÷(4)84 \div (-4)

(c) (56)÷(2)(-56) \div (-2)

Q12

Find the integer whose product with (1)(-1) is:

(a) 27

(b) -31

(c) -1

(d) 1

(e) 0

Q13

If 4756+148+28+5=447 - 56 + 14 - 8 + 2 - 8 + 5 = -4, then find the value of 47+5614+82+85-47 + 56 - 14 + 8 - 2 + 8 - 5 without calculating the full expression.

Q14

Do you remember the Collatz Conjecture from last year? Try a modified version with integers. The rule is — start with any number; if the number is even, take half of it; if the number is odd, multiply it by 3-3 and add 1; repeat. An example sequence is shown below.

Try this with different starting numbers: (21)(-21), (6)(-6), and so on. Describe the patterns you observe.

Q15

In a test, (+4) marks are given for every correct answer and (-2) marks are given for every incorrect answer.

(a) Anita answered all the questions in the test. She scored 40 marks even though 15 of her answers were correct. How many of her answers were incorrect? How many questions are in the test?

(b) Anil scored (-10) marks even though he had 5 correct answers. How many of his answers were incorrect? Did he leave any questions unanswered?

Q16

Pick the pattern — find the operations done by the machine shown below.

Q17

Imagine you're in a place where the temperature drops by 5°C each hour. If the temperature is currently at 8°C, write an expression which denotes the temperature after 4 hours.

Q18

Find 3 consecutive numbers with a product of (a) -6, (b) 120.

Q19

An alien society uses a peculiar currency called 'pibs' with just two denominations of coins — a+13 pibs coin and a -9 pibs coin. You have several of these coins. Is it possible to purchase an item that costs +85 pibs?

Q20

Find the values of:

(a) (32×(18))÷((36))(32 \times (-18)) \div ((-36))

(b) (32)÷((36)×(18))(32) \div ((-36) \times (-18))

(c) (25×(12))÷((45)×(27))(25 \times (-12)) \div ((45) \times (-27))

(d) (280×(7))÷((8)×(35))(280 \times (-7)) \div ((-8) \times (-35))

Q21

Arrange the expressions given below in increasing order:

(a) (348)+(1064)(-348) + (-1064)

(b) (348)(1064)(-348) - (-1064)

(c) 348(1064)348 - (-1064)

(d) (348)×(1064)(-348) \times (-1064)

(e) 348×(1064)348 \times (-1064)

(f) 348×964348 \times 964

Q22

Given that (548)×972=532656(-548) \times 972 = -532656, write the values of:

(a) (547)×972(-547) \times 972

(b) (548)×971(-548) \times 971

(c) (547)×971(-547) \times 971

Q23

Given that 207×(33+7)=5382207 \times (-33 + 7) = -5382, write the value of 207×(337)=___?-207 \times (33 - 7) =\_\_\_?

Q24

Use the numbers 3,2,5,63, -2, 5, -6 exactly once and the operations '+', '-', and 'x' exactly once and brackets as necessary to write an expression such that —

(a) the result is the maximum possible

(b) the result is the minimum possible

Q25

Fill in the blanks in at least 5 different ways with integers:

(a) +×=36\square + \square \times \square = -36

(b) ()×=12(\square - \square) \times \square = 12

(c) (())=1(\square - (\square - \square)) = -1

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