A Tale of Three Intersecting Lines | IT

Question 42

Does there exist a triangle in which a side is also an altitude?

Visualise such a triangle and draw a rough diagram.

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Solution

An altitude is a line from a vertex perpendicular to the opposite side.

Step 1 — Understanding an altitude

Let us imagine a triangle. It has three vertices and three sides. An altitude is a special line segment. It starts from one vertex. It goes straight down to the opposite side. It meets the opposite side at a right angle. A right angle measures 90 degrees.

Altitude  Opposite Side\text{Altitude } \perp \text{ Opposite Side}

Step 2 — Side acting as an altitude

Let us consider a triangle ABC. Let its vertices be A, B, and C. Let us assume one side is also an altitude. Suppose side AB is an altitude. Side AB starts from vertex A. The side opposite to vertex A is BC. So, side AB must be perpendicular to side BC.

Step 3 — What perpendicular means

If side AB is perpendicular to side BC, They must meet at a 90-degree angle. This means the angle at vertex B is 90 degrees. We can write this as:

ABC=90\angle \text{ABC} = \mathbf{90^\circ}

Step 4 — Does such a triangle exist?

A triangle with a 90-degree angle is special. We call it a right-angled triangle. In a right-angled triangle, two sides meet at 90 degrees. These two sides are perpendicular to each other. One of these sides can be an altitude. For example, side AB is an altitude to side BC. Side BC is also an altitude to side AB. So, yes, such a triangle exists.

Yes, such a triangle exists.\boxed{\text{Yes, such a triangle exists.}}

Diagram 1

Answer

(i) Yes, such a triangle exists. (ii) It is a right-angled triangle. (iii) In this triangle, one of the perpendicular sides acts as an altitude to the other.

More questions in IT

Q1

What happens when the three vertices lie on a straight line?

Q2

Construct a triangle in which all the sides are of length 4 cm.

Q3

Context: Construct a triangle in which all the sides are of length 4 cm.

Q. How did you construct this triangle and what tools did you use? Can this construction be done only using a marked ruler (and a pencil)?

Q4

Q. How do we make this construction more efficient?

Q5

Context: Step 2: Construct another arc of radius 4 cm4\text{ cm} from BB. Let CC be the point of intersection of the arcs.

Q. The construction ensures that both ACAC and BCBC are of length 4 cm4\text{ cm}. Can you see why?

Q6
  1. How do we construct triangles that are not equilateral?

  2. Construct a triangle of sidelength 4 cm, 5 cm and 6 cm.

Q7

Context: Construct a triangle of sidelength 4 cm, 5 cm and 6 cm.

Q. How do we construct this triangle more efficiently?

Q8

Construct

Construct triangles having the following sidelengths (all the units are in cm):

(a) 4, 4, 6

(b) 3, 4, 5

(c) 1, 5, 5

(d) 4, 6, 8

(e) 3.5, 3.5, 3.5

Q9

Construct a triangle with sidelengths 3 cm, 4 cm, and 8 cm.

What is happening? Are you able to construct the triangle?

Q10

Here is another set of lengths: 2 cm, 3 cm, and 6 cm. Check if a triangle is possible for these sidelengths.

Q11

Try to find more sets of lengths for which a triangle construction is impossible. See if you can find any pattern in them.

Q12

Context: Clearly, the direct straight-line path from the tent to the tree is shorter than the roundabout path via the pole. In fact, the direct straight-line path is the shortest possible path to the tree from the tent. Will the direct path between any two points be shorter than the roundabout path via a third point? Clearly, the answer is yes.

Q. Can this understanding be used to tell something about the existence of a triangle having sidelengths 10 cm10\text{ cm}, 15 cm15\text{ cm} and 30 cm30\text{ cm}?

Q13

Can we say anything about the existence of a triangle having sidelengths 3 cm, 3 cm and 7 cm? Verify your answer by construction.

Q14

In the rough diagram in Fig. 7.4, is it possible to assign lengths in a different order such such that the direct paths are always coming out to be shorter than the roundabout paths? If this is possible, then a triangle might exist.

Q15

Context: "In the rough diagram in Fig. 7.4, is it possible to assign lengths in a different order such that the direct paths are always coming out to be shorter than the roundabout paths? If this is possible, then a triangle might exist."

Q. Is such rearrangement of lengths possible in the triangle?

Q16

Will this always happen? That is, for any set of lengths, will there be at least two comparisons where the direct length is less than the sum of the other two? Explore for different sets of lengths.

Q17

Further, for a given set of lengths, is it possible to identify which lengths will immediately be less than the sum of the other two, without calculations?

[Hint: Consider the direct lengths in the increasing order.]

Q18

Given three sidelengths, what do we need to compare to check for the existence of a triangle?

Q19

Context: Does a triangle exist with sidelengths 4 cm4\text{ cm}, 5 cm5\text{ cm} and 8 cm8\text{ cm}? This satisfies the triangle inequality: 8<4+5=98 < 4 + 5 = 9

Q. Why do we not need to check the other two sides?

Q20

Now, suppose that a circle of radius 5 cm is constructed, centred at B. Can you draw a rough diagram of the resulting figure?

Q21

Will triangles always exist when a set of lengths satisfies the triangle inequality? How can we be sure?

Q22

Q. Let us study each of these cases by finding the relation between the radii (the smaller two lengths) and AB (longest length).

Q23

Context: Case 2: Circles do not intersect internally

Q. For this case to happen, what should be the relation between the radii and AB?

Q24

Can we use this analysis to tell if a triangle exists when the lengths satisfy the triangle inequality?

Q25

How will the two circles turn out for a set of lengths that do not satisfy the triangle inequality? Find 3 examples of sets of lengths for which the circles:

(a) touch each other at a point,

(b) do not intersect.

Q26

Frame a complete procedure that can be used to check the existence of a triangle.

Q27

We have seen that triangles do not exist for all sets of sidelengths. Is there a combination of measurements in the case of two sides and the included angle where a triangle is not possible? Justify your answer using what you observe during construction.

Q28

Do triangles exist for every combination of two angles and their included side? Explore.

Q29

Find examples of measurements of two angles with the included side where a triangle is not possible.

Q30

It is clear that if the line from B is "inclined" sufficiently to the right, then it will not meet the line ll.

(a) Try to find a possible B\angle B (marked in the figure) for this to happen. (b) What could be smallest value of B\angle B for the lines to not meet?

Q31

Like the triangle inequality, can you form a rule that describes the two angles for which a triangle is possible?

Can the sum of the two angles be used for framing this rule?

Q32

Context: Let us take two angles, say 6060^\circ and 7070^\circ, whose sum is less than 180180^\circ. Let the included side be 5 cm.

Q. What could the measure of the third angle be? Does this measure change if the base length is changed to some other value, say 7 cm? Construct and find out.

Q33

In general, once the two angles are fixed, does the third angle depend on the included sidelength? Try with different pairs of angles and lengths.

Q34

Try experimenting with different triangles to see if there is a relation between any two angles and the third one. To find this relation, what data will you keep track of and how will you organise the data you collect?

Q35

Context: Consider a triangle ABC with B=50\angle B = 50^\circ and C=70\angle C = 70^\circ. Suppose we construct a line XY parallel to BC through vertex A.

Q. We can see new angles being formed here: XAB\angle XAB, and YAC\angle YAC. What are their values?

Q36

Angle Sum Property

What can we say about the sum of the angles of any triangle?

Q37

There is a convenient way of verifying the angle sum property by folding a triangular cut-out of a paper. Do you see how this shows that the sum of the angles in this triangle is 180180^\circ?

Q38

Find the exterior angle for different measures of A\angle A and B\angle B. Do you see any relation between the exterior angle and these two angles?

[Hint: From angle sum property, we have A+B+ACB=180\angle A + \angle B + \angle ACB = 180^\circ.]

We also have ACD+ACB=180\angle ACD + \angle ACB = 180^\circ, since they form a straight angle.

What does this show?

Q39

What would the altitude from A to BC be in this triangle?

Q40

Construct an arbitrary triangle. Label the vertices A, B, C taking BC to be the base.

Construct the altitude from A to BC,

Q41

Context: Construction of the Altitudes of a Triangle Construct an arbitrary triangle. Label the vertices AA, BB, CC taking BCBC to be the base. Construct the altitude from AA to BCBC.

Q. Constructing the altitude using just a ruler is not accurate. To get a more precise angle of 9090^\circ, we use a set square along with a ruler.

Can you see how to do this?

Q42

Does there exist a triangle in which a side is also an altitude?

Visualise such a triangle and draw a rough diagram.

Q43

Context: In our study of triangles, we have encountered the following types of triangles; equilateral, isosceles, scalene and right-angled triangles.

Q. Did you spot any other type of triangle?

Q44

What are the other types of triangles based on angle measures?

Q45

What could an acute-angled triangle be? Can we define it as a triangle with one acute angle? Why not?

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