Expressions Using Letter-Numbers | FIO

Question 15

A local train from Yahapur to Vahapur stops at three stations at equal distances along the way. The time taken in minutes to travel from one station to the next station is the same and is denoted by tt. The train stops for 2 minutes at each of the three stations.

(a) If t=4t = 4, what is the time taken to travel from Yahapur to Vahapur?

(b) What is the algebraic expression for the time taken to travel from Yahapur to Vahapur? [Hint: Draw a rough diagram to visualise the situation]

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Solution

We will add the time spent travelling and the time spent waiting.

Step 1 — Visualising the journey

Let us draw a diagram of the train's journey. The train starts at Yahapur (Y). It stops at three stations: S1, S2, S3. Then it reaches Vahapur (V). The stations are equally spaced.

Diagram 1

We can see there are 4 travel segments. Each segment takes tt minutes. So, the total travel time is 4×t4 \times t. There are 3 stations where the train stops. Each stop is for 2 minutes. So, the total stopping time is 3×23 \times 2.

Let us find the total time for the journey. Total time = (Total travel time) + (Total stopping time).

Step 2 — Calculating time for t=4t=4 minutes

We are given that t=4t = 4 minutes. Let us calculate the total travel time first. Total travel time = 4×t4 \times t minutes. =4×4= 4 \times 4 =16 minutes= 16 \text{ minutes}

Next, let us calculate the total stopping time. Total stopping time = 3×23 \times 2 minutes. =6 minutes= 6 \text{ minutes}

Now, we add these two times together. Total time = Total travel time + Total stopping time. =16 minutes+6 minutes= 16 \text{ minutes} + 6 \text{ minutes}

22 minutes\boxed{22 \text{ minutes}}

Step 3 — Finding the algebraic expression

We need an expression for the total time. This expression will use the variable tt. We already found the total travel time. Total travel time = 4×t4 \times t minutes. =4t minutes= 4t \text{ minutes}

We also found the total stopping time. Total stopping time = 3×23 \times 2 minutes. =6 minutes= 6 \text{ minutes}

Now, we add these two expressions. Total time = Total travel time + Total stopping time. =4t+6 minutes= 4t + 6 \text{ minutes}

4t+6 minutes\boxed{4t + 6 \text{ minutes}}

Answer

(a) The time taken is 22 minutes. (b) The algebraic expression is 4t+64t + 6 minutes.

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