Arithmetic Expressions | FIO

Question 15

Read the situations given below. Write appropriate expressions for each of them and find their values.

(a) The district market in Begur operates on all seven days of a week. Rahim supplies 9 kg of mangoes each day from his orchard and Shyam supplies 11 kg of mangoes each day from his orchard to this market. Find the amount of mangoes supplied by them in a week to the local district market.

(b) Binu earns ₹20,000 per month. She spends ₹5,000 on rent, ₹5,000 on food, and ₹2,000 on other expenses every month. What is the amount Binu will save by the end of a year?

(c) During the daytime a snail climbs 3 cm up a post, and during the night while asleep, accidentally slips down by 2 cm. The post is 10 cm high, and a delicious treat is on its top. In how many days will the snail get the treat?

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Solution

We will solve each situation by writing appropriate expressions and finding their values.

Step 1 — Rahim's weekly supply

Rahim supplies mangoes every day. There are seven days in a week. We multiply his daily supply by 7.

Rahim’s daily supply=9 kg\text{Rahim's daily supply} = 9 \text{ kg}

Number of days in a week=7\text{Number of days in a week} = 7

Rahim’s weekly supply=9×7\text{Rahim's weekly supply} = 9 \times 7

=63 kg= 63 \text{ kg}

Rahim supplies 63 kg of mangoes per week\boxed{\text{Rahim supplies } 63 \text{ kg of mangoes per week}}

Step 2 — Shyam's weekly supply

Shyam also supplies mangoes every day. There are seven days in a week. We multiply his daily supply by 7.

Shyam’s daily supply=11 kg\text{Shyam's daily supply} = 11 \text{ kg}

Number of days in a week=7\text{Number of days in a week} = 7

Shyam’s weekly supply=11×7\text{Shyam's weekly supply} = 11 \times 7

=77 kg= 77 \text{ kg}

Shyam supplies 77 kg of mangoes per week\boxed{\text{Shyam supplies } 77 \text{ kg of mangoes per week}}

Step 3 — Total weekly supply

We add Rahim's and Shyam's weekly supplies. This gives the total mangoes supplied.

Total weekly supply=Rahim’s supply+Shyam’s supply\text{Total weekly supply} = \text{Rahim's supply} + \text{Shyam's supply}

=63+77= 63 + 77

=140 kg= 140 \text{ kg}

Total mangoes supplied in a week=140 kg\boxed{\text{Total mangoes supplied in a week} = 140 \text{ kg}}

Step 4 — Binu's total monthly expenses

Binu has three types of expenses each month. We add these expenses together.

Rent expense=5,000\text{Rent expense} = ₹5,000

Food expense=5,000\text{Food expense} = ₹5,000

Other expenses=2,000\text{Other expenses} = ₹2,000

Total monthly expenses=5000+5000+2000\text{Total monthly expenses} = 5000 + 5000 + 2000

=12000 ₹= 12000 \text{ ₹}

Binu’s total monthly expenses=12,000\boxed{\text{Binu's total monthly expenses} = ₹12,000}

Step 5 — Binu's monthly savings

Binu's monthly savings are her income minus her expenses. We subtract the total expenses from her monthly income.

Monthly income=20,000\text{Monthly income} = ₹20,000

Total monthly expenses=12,000\text{Total monthly expenses} = ₹12,000

Monthly savings=2000012000\text{Monthly savings} = 20000 - 12000

=8000 ₹= 8000 \text{ ₹}

Binu’s monthly savings=8,000\boxed{\text{Binu's monthly savings} = ₹8,000}

Step 6 — Binu's yearly savings

There are 12 months in a year. We multiply her monthly savings by 12.

Monthly savings=8,000\text{Monthly savings} = ₹8,000

Number of months in a year=12\text{Number of months in a year} = 12

Yearly savings=8000×12\text{Yearly savings} = 8000 \times 12

=96000 ₹= 96000 \text{ ₹}

Binu’s yearly savings=96,000\boxed{\text{Binu's yearly savings} = ₹96,000}

Step 7 — Snail's net climb per day

The snail climbs up during the day. It slips down during the night. We find the net distance covered each day.

Climb during day=3 cm\text{Climb during day} = 3 \text{ cm}

Slip during night=2 cm\text{Slip during night} = 2 \text{ cm}

Net climb per day=32\text{Net climb per day} = 3 - 2

=1 cm= 1 \text{ cm}

Snail’s net climb per day=1 cm\boxed{\text{Snail's net climb per day} = 1 \text{ cm}}

Diagram 1

Step 8 — Height to reach before final climb

The post is 10 cm high. The snail will not slip once it reaches the top. Its final climb is 3 cm. So, it needs to reach 10310 - 3 cm before the last day.

Total post height=10 cm\text{Total post height} = 10 \text{ cm}

Final climb distance=3 cm\text{Final climb distance} = 3 \text{ cm}

Height to reach before final day=103\text{Height to reach before final day} = 10 - 3

=7 cm= 7 \text{ cm}

Snail needs to reach 7 cm before the last day\boxed{\text{Snail needs to reach } 7 \text{ cm before the last day}}

Step 9 — Days to reach the target height

The snail climbs 1 cm net each day. It needs to reach 7 cm. We divide the target height by the net climb per day.

Target height=7 cm\text{Target height} = 7 \text{ cm}

Net climb per day=1 cm\text{Net climb per day} = 1 \text{ cm}

Days to reach 7 cm=71\text{Days to reach 7 cm} = \frac{7}{1}

=7 days= 7 \text{ days}

It takes 7 days to reach 7 cm\boxed{\text{It takes } 7 \text{ days to reach } 7 \text{ cm}}

Step 10 — Total days to get the treat

After 7 days, the snail is at 7 cm. On the 8th day, it climbs 3 cm. It reaches the top of the post. It gets the treat and does not slip.

Days to reach 7 cm=7 days\text{Days to reach 7 cm} = 7 \text{ days}

Days for final climb=1 day\text{Days for final climb} = 1 \text{ day}

Total days=7+1\text{Total days} = 7 + 1

=8 days= 8 \text{ days}

The snail will get the treat in 8 days\boxed{\text{The snail will get the treat in } 8 \text{ days}}

Answer

(a) The amount of mangoes supplied by them in a week to the local district market is 140 kg. (b) The amount Binu will save by the end of a year is ₹96,000. (c) The snail will get the treat in 8 days.

More questions in FIO

Q1

Fill in the blanks to make the expressions equal on both sides of the == sign:

(a) 13+4=+613 + 4 = \underline{\quad} + 6

(b) 22+=6×522 + \underline{\quad} = 6 \times 5

(c) 8×=64÷28 \times \underline{\quad} = 64 \div 2

(d) 34=2534 - \underline{\quad} = 25

Q2

Arrange the following expressions in ascending (increasing) order of their values.

(a) 671967 - 19

(b) 672067 - 20

(c) 35+2535 + 25

(d) 5×115 \times 11

(e) 120÷3120 \div 3

Q3

Find the values of the following expressions by writing the terms in each case.

(a) 287+828 - 7 + 8

(b) 392×6+1139 - 2 \times 6 + 11

(c) 4010+10+1040 - 10 + 10 + 10

(d) 4810×2+16÷248 - 10 \times 2 + 16 \div 2

(e) 6×34×8×56 \times 3 - 4 \times 8 \times 5

Q4

Write a story/situation for each of the following expressions and find their values.

(a) 89+211089 + 21 - 10

(b) 5×1265 \times 12 - 6

(c) 4×9+2×64 \times 9 + 2 \times 6

Q5

For each of the following situations, write the expression describing the situation, identify its terms and find the value of the expression.

(a) Queen Alia gave 100 gold coins to Princess Elsa and 100 gold coins to Princess Anna last year. Princess Elsa used the coins to start a business and doubled her coins. Princess Anna bought jewellery and has only half of the coins left. Write an expression describing how many gold coins Princess Elsa and Princess Anna together have.

(b) A metro train ticket between two stations is ₹40 for an adult and ₹20 for a child. What is the total cost of tickets:

(i) for four adults and three children?
(ii) for two groups having three adults each?

(c) Find the total height of the window by writing an expression describing the relationship among the measurements shown in the picture.

Q6

Add brackets at appropriate places in the expressions such that they lead to the values indicated.

(a) 349+12=1334 - 9 + 12 = 13

(b) 56148=3456 - 14 - 8 = 34

(c) 2212+10+22=22-22 - 12 + 10 + 22 = -22

Q7

Using only reasoning of how terms change their values, fill the blanks to make the expressions on either side of the equality (==) equal.

(a) 423+=419+423 + \underline{\quad\quad} = 419 + \underline{\quad\quad}

(b) 20768=210207 - 68 = 210 - \underline{\quad\quad}

Q8

Using the numbers 2, 3 and 5, and the operators '+' and '-', and brackets, as necessary, generate expressions to give as many different values as possible. For example, 23+5=42 - 3 + 5 = 4 and 3(52)=03 - (5 - 2) = 0.

Q9

Whenever Jasoda has to subtract 9 from a number, she subtracts 10 and adds 1 to it. For example, 369=26+136 - 9 = 26 + 1.

(a) Do you think she always gets the correct answer? Why?

(b) Can you think of other similar strategies? Give some examples.

Q10

Consider the two expressions: a) 7314+173 - 14 + 1, b) 7314173 - 14 - 1. For each of these expressions, identify the expressions from the following collection that are equal to it.

(a) 73(14+1)73 - (14 + 1)

(b) 73(141)73 - (14 - 1)

(c) 73+(14+1)73 + (-14 + 1)

(d) 73+(141)73 + (-14 - 1)

Q11

Figure it Out

  1. Fill in the blanks with numbers, and boxes by signs, so that the expressions on both sides are equal.

(a) 3×(6+7)=3×6+3×73 \times (6 + 7) = 3 \times 6 + 3 \times 7

(b) (8+3)×4=8×4+3×4(8 + 3) \times 4 = 8 \times 4 + 3 \times 4

(c) 3×(5+8)=3×5  3×   3 \times (5 + 8) = 3 \times 5 \ \Box\ 3 \times \underline{\ \ \ }

(d) (9+2)×4=9×4  2×   (9 + 2) \times 4 = 9 \times 4 \ \Box\ 2 \times \underline{\ \ \ }

(e) 3×(   +4)=3    +   3 \times (\underline{\ \ \ } + 4) = 3 \ \underline{\ \ \ } + \underline{\ \ \ }

(f) (   +6)×4=13×4+   (\underline{\ \ \ } + 6) \times 4 = 13 \times 4 + \underline{\ \ \ }

(g) 3×(   +   )=3×5+3×23 \times (\underline{\ \ \ } + \underline{\ \ \ }) = 3 \times 5 + 3 \times 2

(h) (   +   )×   =2×4+3×4(\underline{\ \ \ } + \underline{\ \ \ }) \times \underline{\ \ \ } = 2 \times 4 + 3 \times 4

(i) 5×(92)=5×95×   5 \times (9 - 2) = 5 \times 9 - 5 \times \underline{\ \ \ }

(j) (52)×7=5×72×   (5 - 2) \times 7 = 5 \times 7 - 2 \times \underline{\ \ \ }

(k) 5×(83)=5×8  5×   5 \times (8 - 3) = 5 \times 8 \ \Box\ 5 \times \underline{\ \ \ }

(l) (83)×7=8×7  3×7(8 - 3) \times 7 = 8 \times 7 \ \Box\ 3 \times 7

(m) 5×(12   )=     5×   5 \times (12 - \underline{\ \ \ }) = \underline{\ \ \ } \ \Box\ 5 \times \underline{\ \ \ }

(n) (15   )×7=     6×7(15 - \underline{\ \ \ }) \times 7 = \underline{\ \ \ } \ \Box\ 6 \times 7

(o) 5×(      )=5×95×45 \times (\underline{\ \ \ } - \underline{\ \ \ }) = 5 \times 9 - 5 \times 4

(p) (      )×   =17×79×7(\underline{\ \ \ } - \underline{\ \ \ }) \times \underline{\ \ \ } = 17 \times 7 - 9 \times 7

Q12

In the boxes below, fill '<', '>' or '=' after analysing the expressions on the LHS and RHS. Use reasoning and understanding of terms and brackets to figure this out and not by evaluating the expressions.

(a) (83)×29  (38)×29(8 - 3) \times 29 \ \square\ (3 - 8) \times 29

(b) 15+9×18  (15+9)×1815 + 9 \times 18 \ \square\ (15 + 9) \times 18

(c) 23×(179)  23×17+23×923 \times (17 - 9) \ \square\ 23 \times 17 + 23 \times 9

(d) (3428)×42  34×4228×42(34 - 28) \times 42 \ \square\ 34 \times 42 - 28 \times 42

Q13

Here is one way to make 14: 2×(1+6)=142 \times ( 1 + 6 ) = 14. Are there other ways of getting 14? Fill them out below:

(a) ×(+)=14\underline{\quad} \times (\underline{\quad} + \underline{\quad}) = 14

(b) ×(+)=14\underline{\quad} \times (\underline{\quad} + \underline{\quad}) = 14

(c) ×(+)=14\underline{\quad} \times (\underline{\quad} + \underline{\quad}) = 14

(d) ×(+)=14\underline{\quad} \times (\underline{\quad} + \underline{\quad}) = 14

Q14

Find out the sum of the numbers given in each picture below in at least two different ways. Describe how you solved it through expressions.

Q15

Read the situations given below. Write appropriate expressions for each of them and find their values.

(a) The district market in Begur operates on all seven days of a week. Rahim supplies 9 kg of mangoes each day from his orchard and Shyam supplies 11 kg of mangoes each day from his orchard to this market. Find the amount of mangoes supplied by them in a week to the local district market.

(b) Binu earns ₹20,000 per month. She spends ₹5,000 on rent, ₹5,000 on food, and ₹2,000 on other expenses every month. What is the amount Binu will save by the end of a year?

(c) During the daytime a snail climbs 3 cm up a post, and during the night while asleep, accidentally slips down by 2 cm. The post is 10 cm high, and a delicious treat is on its top. In how many days will the snail get the treat?

Q16

Melvin reads a two-page story every day except on Tuesdays and Saturdays. How many stories would he complete reading in 8 weeks? Which of the expressions below describes this scenario?

(a) 5 × 2 × 8

(b) (7 - 2) × 8

(c) 8 × 7

(d) 7 × 2 × 8

(e) 7 × 5 - 2

(f) (7 + 2) × 8

(g) 7 × 8 - 2 × 8

(h) (7 - 5) × 8

Q17

Find different ways of evaluating the following expressions:

(a) 1 - 2 + 3 - 4 + 5 - 6 + 7 - 8 + 9 - 10

(b) 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1

Q18

Compare the following pairs of expressions using '<', '>' or '=' or by reasoning.

(a) 497+8497+849 - 7 + 8 \quad \square \quad 49 - 7 + 8

(b) 83×421883×401883 \times 42 - 18 \quad \square \quad 83 \times 40 - 18

(c) 14517×814517×6145 - 17 \times 8 \quad \square \quad 145 - 17 \times 6

(d) 23×483523×(4835)23 \times 48 - 35 \quad \square \quad 23 \times (48 - 35)

(e) (1611)×1211×12+16×12(16 - 11) \times 12 \quad \square \quad -11 \times 12 + 16 \times 12

(f) (7653)×8888×(5376)(76 - 53) \times 88 \quad \square \quad 88 \times (53 - 76)

(g) 25×(42+16)25×(43+15)25 \times (42 + 16) \quad \square \quad 25 \times (43 + 15)

(h) 36×(2816)35×(2715)36 \times (28 - 16) \quad \square \quad 35 \times (27 - 15)

Q19

Identify which of the following expressions are equal to the given expression without computation. You may rewrite the expressions using terms or removing brackets. There can be more than one expression which is equal to the given expression.

(a) 83371283 - 37 - 12

(i) 84381284 - 38 - 12

(ii) 84(37+12)84 - (37 + 12)

(iii) 83381383 - 38 - 13

(iv) 37+8312- 37 + 83 - 12

(b) 93+37×44+7693 + 37 \times 44 + 76

(i) 37+93×44+7637 + 93 \times 44 + 76

(ii) 93+37×76+4493 + 37 \times 76 + 44

(iii) (93+37)×(44+76)(93 + 37) \times (44 + 76)

(iv) 37×44+93+7637 \times 44 + 93 + 76

Q20

Choose a number and create ten different expressions having that value.

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