Playing with Constructions | IT

Question 11

In a rectangle ABCD with AB = 7 cm and BC = 4 cm, X is a point that can be moved anywhere along the side AD, and Y is a point that can be moved anywhere along the side BC.

Q. At which positions will the points X and Y be at their closest? When do you think they will be the farthest? What does your intuition say? Discuss with your classmates.

Question diagram 1
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Solution

The distance between X and Y changes as they move. We need to find the smallest and largest possible distances.

Step 1 — Understanding the Rectangle Let us draw a rectangle ABCD. The length AB is 7 cm. The width BC is 4 cm. Point X is on side AD. Point Y is on side BC.

Diagram 1

Step 2 — Finding the Closest Distance Let us think about the shortest path. This path is between X and Y. Sides AD and BC are parallel. The shortest distance between parallel lines is perpendicular. If X and Y are at the same height. The line segment XY is perpendicular. It is perpendicular to AD and BC. So the distance XY equals the rectangle's length. The length of the rectangle is AB.

XY=ABXY = AB XY=7 cmXY = \mathbf{7 \text{ cm}}

So, X and Y are closest when they are directly opposite. This means AX=BYAX = BY. Or, we can say DX=CYDX = CY. The distance between them will be 7 cm.

Diagram 2

Step 3 — Finding the Farthest Distance Let us think about the longest path. This path is between X and Y. Imagine X is at one corner of side AD. Let X be at point A. Then Y can be anywhere on side BC. The distance AY will be longest. This happens when Y is at corner C. Corner C is farthest from A on BC. So, the distance AC is a diagonal. It is a diagonal of the rectangle. Let us use the Pythagorean theorem. This finds the length of AC. Triangle ABC is a right-angled triangle. AB is 7 cm. BC is 4 cm.

AC2=AB2+BC2AC^2 = AB^2 + BC^2 AC2=72+42AC^2 = \mathbf{7}^2 + \mathbf{4}^2 AC2=49+16AC^2 = \mathbf{49} + \mathbf{16} AC2=65AC^2 = \mathbf{65} AC=65AC = \sqrt{\mathbf{65}}

The value of 65\sqrt{65} is about 8.06 cm. Similarly, if X is at D. The farthest point Y on BC is B. The distance DB is also a diagonal. So, X and Y are farthest at opposite corners. This means X is at A and Y is at C. Or X is at D and Y is at B. The distance between them will be 65 cm\sqrt{\mathbf{65} \text{ cm}}.

Diagram 3

Step 4 — Intuition Our intuition tells us something. The closest points are directly opposite each other. The line connecting them is perpendicular. It is perpendicular to both lines. For the farthest points, we want the longest segment. This happens at the 'extreme' ends. These extreme ends are the corners. Connecting opposite corners gives the longest distance.

Answer

(i) X and Y will be at their closest when they are at the same height. This means AX=BYAX = BY. The distance will be 7 cm. (ii) X and Y will be at their farthest when they are at opposite corners of the rectangle. This means X is at A and Y is at C, or X is at D and Y is at B. The distance will be 65 cm\sqrt{\mathbf{65} \text{ cm}}. (iii) My intuition says the closest points are directly opposite each other, and the farthest points are at the corners that are furthest apart.

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Q11

In a rectangle ABCD with AB = 7 cm and BC = 4 cm, X is a point that can be moved anywhere along the side AD, and Y is a point that can be moved anywhere along the side BC.

Q. At which positions will the points X and Y be at their closest? When do you think they will be the farthest? What does your intuition say? Discuss with your classmates.

Q12

In a rectangle ABCD with AB = 7 cm and BC = 4 cm, X is a point that can be moved anywhere along the side AD, and Y is a point that can be moved anywhere along the side BC.

Q. Verify your guesses by placing the points X and Y on the sides and measure how near or far they are. The distance between X and Y can be obtained by measuring the length of the line XY.

(i) How does the minimum distance between the points X and Y compare to the length of AB? (ii) Change the positions of X and Y to check if there are other positions where they are at their nearest or farthest. How will you keep track of the lengths XY for different positions of X and Y?

Q13

In a rectangle ABCD with AB = 7 cm and BC = 4 cm, X is a point that can be moved anywhere along the side AD, and Y is a point that can be moved anywhere along the side BC.

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Q14

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Q15

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and so on.

In each of these cases, observe

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Q16

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Q17

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Q19

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Q20

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Q21

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Q22

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Q24

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Q39

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Q40

B) (From Construct above (page no. 211).)

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