Pair of Linear Equations in Two Variables | Exercise 3.1

Question 2

  1. On comparing the ratios a1a2\frac{a_1}{a_2}, b1b2\frac{b_1}{b_2} and c1c2\frac{c_1}{c_2}, find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident:

(i) 5x4y+8=05x - 4y + 8 = 0 7x+6y9=07x + 6y - 9 = 0

(ii) 9x+3y+12=09x + 3y + 12 = 0 18x+6y+24=018x + 6y + 24 = 0

(iii) 6x3y+10=06x - 3y + 10 = 0 2xy+9=02x - y + 9 = 0

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Solution

We compare the ratios of coefficients to find the nature of the lines.

Step 1 — Understand the conditions

Let the two linear equations be a1x+b1y+c1=0a_1x + b_1y + c_1 = 0 and a2x+b2y+c2=0a_2x + b_2y + c_2 = 0.

We use these conditions:

If a1a2b1b2\frac{a_1}{a_2} \neq \frac{b_1}{b_2}, the lines intersect at one point. If a1a2=b1b2c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}, the lines are parallel. If a1a2=b1b2=c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}, the lines are coincident.

Diagram 1

Step 2 — Solve part (i)

The given equations are 5x4y+8=05x - 4y + 8 = 0 and 7x+6y9=07x + 6y - 9 = 0.

Here, a1=5a_1 = \mathbf{5}, b1=4b_1 = \mathbf{-4}, c1=8c_1 = \mathbf{8}.

And a2=7a_2 = \mathbf{7}, b2=6b_2 = \mathbf{6}, c2=9c_2 = \mathbf{-9}.

Let's find the ratios.

a1a2=57\frac{a_1}{a_2} = \frac{5}{7}

b1b2=46\frac{b_1}{b_2} = \frac{-4}{6}

=23= \frac{-2}{3}

We compare 57\frac{5}{7} and 23\frac{-2}{3}.

5723\frac{5}{7} \neq \frac{-2}{3}

So, a1a2b1b2\frac{a_1}{a_2} \neq \frac{b_1}{b_2}.

Intersecting lines\boxed{\text{Intersecting lines}}

Step 3 — Solve part (ii)

The given equations are 9x+3y+12=09x + 3y + 12 = 0 and 18x+6y+24=018x + 6y + 24 = 0.

Here, a1=9a_1 = \mathbf{9}, b1=3b_1 = \mathbf{3}, c1=12c_1 = \mathbf{12}.

And a2=18a_2 = \mathbf{18}, b2=6b_2 = \mathbf{6}, c2=24c_2 = \mathbf{24}.

Let's find the ratios.

a1a2=918\frac{a_1}{a_2} = \frac{9}{18}

=12= \frac{1}{2}

b1b2=36\frac{b_1}{b_2} = \frac{3}{6}

=12= \frac{1}{2}

c1c2=1224\frac{c_1}{c_2} = \frac{12}{24}

=12= \frac{1}{2}

We compare the ratios.

12=12=12\frac{1}{2} = \frac{1}{2} = \frac{1}{2}

So, a1a2=b1b2=c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}.

Coincident lines\boxed{\text{Coincident lines}}

Step 4 — Solve part (iii)

The given equations are 6x3y+10=06x - 3y + 10 = 0 and 2xy+9=02x - y + 9 = 0.

Here, a1=6a_1 = \mathbf{6}, b1=3b_1 = \mathbf{-3}, c1=10c_1 = \mathbf{10}.

And a2=2a_2 = \mathbf{2}, b2=1b_2 = \mathbf{-1}, c2=9c_2 = \mathbf{9}.

Let's find the ratios.

a1a2=62\frac{a_1}{a_2} = \frac{6}{2}

=3= 3

b1b2=31\frac{b_1}{b_2} = \frac{-3}{-1}

=3= 3

c1c2=109\frac{c_1}{c_2} = \frac{10}{9}

We compare the ratios.

3=31093 = 3 \neq \frac{10}{9}

So, a1a2=b1b2c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}.

Parallel lines\boxed{\text{Parallel lines}}

Answer

(i) The lines intersect at a point. (ii) The lines are coincident. (iii) The lines are parallel.

More questions in Exercise 3.1

Q1

Form the pair of linear equations in the following problems, and find their solutions graphically.

(i) 10 students of Class X took part in a Mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.

(ii) 5 pencils and 7 pens together cost ₹ 50, whereas 7 pencils and 5 pens together cost ₹ 46. Find the cost of one pencil and that of one pen.

Q2
  1. On comparing the ratios a1a2\frac{a_1}{a_2}, b1b2\frac{b_1}{b_2} and c1c2\frac{c_1}{c_2}, find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident:

(i) 5x4y+8=05x - 4y + 8 = 0 7x+6y9=07x + 6y - 9 = 0

(ii) 9x+3y+12=09x + 3y + 12 = 0 18x+6y+24=018x + 6y + 24 = 0

(iii) 6x3y+10=06x - 3y + 10 = 0 2xy+9=02x - y + 9 = 0

Q3
  1. On comparing the ratios a1a2\frac{a_1}{a_2}, b1b2\frac{b_1}{b_2} and c1c2\frac{c_1}{c_2}, find out whether the following pair of linear equations are consistent, or inconsistent.

(i) 3x+2y=53x + 2y = 5; 2x3y=72x - 3y = 7

(ii) 2x3y=82x - 3y = 8; 4x6y=94x - 6y = 9

(iii) 32x+53y=7\frac{3}{2}x + \frac{5}{3}y = 7; 9x10y=149x - 10y = 14

(iv) 5x3y=115x - 3y = 11; 10x+6y=22-10x + 6y = -22

(v) 43x+2y=8\frac{4}{3}x + 2y = 8; 2x+3y=122x + 3y = 12

Q4
  1. Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically:

(i) x+y=5x + y = 5, 2x+2y=102x + 2y = 10

(ii) xy=8x - y = 8, 3x3y=163x - 3y = 16

(iii) 2x+y6=02x + y - 6 = 0, 4x2y4=04x - 2y - 4 = 0

(iv) 2x2y2=02x - 2y - 2 = 0, 4x4y5=04x - 4y - 5 = 0

Q5
  1. Half the perimeter of a rectangular garden, whose length is 4 m4\text{ m} more than its width, is 36 m36\text{ m}. Find the dimensions of the garden.
Q6
  1. Given the linear equation 2x+3y8=02x + 3y - 8 = 0, write another linear equation in two variables such that the geometrical representation of the pair so formed is:

(i) intersecting lines

(ii) parallel lines

(iii) coincident lines

Q7
  1. Draw the graphs of the equations xy+1=0x - y + 1 = 0 and 3x+2y12=03x + 2y - 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the xx-axis, and shade the triangular region.
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